trying to replace an array of strings with a new array

Question

I want to repalce an array with a new one but only the first string is replaced. The new array is from a mysql table so I cant specify the exact strings.

$str = "##Random Stirng## ..... ##Random Stirng##";
$pattern = array ("str1" => "first replacement", "str2" => "second replacement");
$replacement = array('/##[^#]+##/','/##[^#]+##/');
echo preg_replace($replacement, $pattern, $str);

I want to replace the first IP-Address with the first replacement and the secon IP-address with the second replacement but instead both IP-Addresses are replaced with the first replacement.

1) You've exchanged pattern & replacement in the preg_replace call. 2) Please, give some example strings and expected result. — Toto
– Toto, Commented Jul 23, 2019 at 10:04
seems like, first replacement become input for second replacement. works based upon reference itself. — CoronaVirus
– CoronaVirus, Commented Jul 23, 2019 at 10:06
"str2" => "second replacement missing double quotes at the end — Rakesh Jakhar
– Rakesh Jakhar, Commented Jul 23, 2019 at 10:07
@RakeshJakhar seems like that is typo while raising this question itself. — CoronaVirus
– CoronaVirus, Commented Jul 23, 2019 at 10:08

Abdul Alsabbagh · Accepted Answer · 2019-07-25 12:19:06Z

2

preg_replace_callback is your friend:

$str = "##Random String## ..... ##Random String##";
$replacement = array ("first replacement", "second replacement");
$i = 0;
$res = preg_replace_callback(
            '/##[^#]+##/', 
            function($m) use(&$i, $replacement) {
                return $replacement[$i++];
            },
            $str);
echo $res;

Output:

first replacement ..... second replacement

edited Jul 25, 2019 at 12:19

Abdul Alsabbagh

374 bronze badges

answered Jul 23, 2019 at 17:10

Toto

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1 Comment

Abdul Alsabbagh Over a year ago

thank you very much. I didnt understand how preg replace callback worked so I had to read about it first. but it worked.

Abdul Alsabbagh · Accepted Answer · 2019-07-25 07:48:33Z

0

You need to use str_replace

$str = "##Random Stirng## ..... ##Random Stirng##";
$pattern = array("Random Stirng", "Random Stirng");
$replacement = array('1','2');
echo str_replace($pattern, $replacement, $str);

edited Jul 25, 2019 at 7:48

Abdul Alsabbagh

374 bronze badges

answered Jul 23, 2019 at 10:08

Rakesh Jakhar

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1 Comment

Abdul Alsabbagh Over a year ago

this is only an example. I have a big mysql table with many IP-adresses that need to be replaced. That's why I put them between the "##".

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