passing function parameter names as strings

Question

I'm working with an API that has dozens of parameters in a given function:

api.update_customer(a='', b='', c='', ..., x='', y='', z='')

I'll only need to update one or a few parameters when I call it, for instance:

api.update_customer(email='[email protected]')

...but I won't know in advance which object needs updating (maybe email, maybe phone number, etc).

How can I build a wrapper around this call so I can pass in both the parameter name and its new value?

def update_customer_details(key, value):
    api.update_customer(key=value)

search for python decorators. That's what you are looking for — mad_
– mad_, Commented Aug 23, 2019 at 18:24

Daniel Roseman · Accepted Answer · 2019-08-23 18:25:59Z

4

You don't need to write a wrapper. Just pass a dict using keyword expansion.

params = {'email': '[email protected]'}
api.update_customer(**params)

answered Aug 23, 2019 at 18:25

Daniel Roseman

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Comments

Chrismon Chin · Accepted Answer · 2019-08-23 18:33:45Z

1

To expand on Daniel Roseman answer for an example on how it gets used:

def test2(x=None):
    print(x)

def test(**kwarg):
    test2(**kwarg)

test(x=5)

output: 5

answered Aug 23, 2019 at 18:33

Chrismon Chin

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kederrac · Accepted Answer · 2019-08-23 19:21:56Z

0

you can try:

api.update_customer(field='my_field', value='my_value', *args, **kwrgs)

answered Aug 23, 2019 at 19:21

kederrac

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