AWS API Gateway Lambda regex not working/ Java

Question

I am trying to match below regular expression for a specific response returned by Lambda function in java. But it does not seem to be working.

Lambda Error Regex -

.*"status:\s"422.*

Lambda error response format(response object is a POJO) -

{
  "id": "3sghsh3232",
  "status": 422,
  "responseCode": "INVALID-DATA",
  "message": "Please provide a valid data",
  "time": "2019-08-30T06:16:20.976",
  "errors": [
    {
      "code": "422",
      "message": "Missing fields"
    }
  ]
}

Tried expressions -

".*\\\"status\\\":422.*"
.*422(.|\n)*
.*422.*

Why not parse the json itself?

The fourth bird
– The fourth bird

2019-08-30 07:55:12 +00:00
Commented Aug 30, 2019 at 7:55 — The fourth bird
– The fourth bird, Commented Aug 30, 2019 at 7:55

amittn · Accepted Answer · 2019-08-30 10:29:26Z

1

I think this should work try it out at regex101

\W*((?i)\"status\"(?-i))\:[\s]+422\,$   
or
\W*((?i)\"status\")\:\s+422\,$
or
\W*(\"status\")\:*\s422\,$

\W* matches any non-word character (equal to [^a-zA-Z0-9_])
(?i) match the remainder of the pattern with the following effective flags:gmi
\" matches the character " literally (case insensitive)
\s matches any whitespace character (equal to [\r\n\t\f\v ])
\, matches the character , literally (case sensitive)

edited Aug 30, 2019 at 10:29

answered Aug 30, 2019 at 7:40

amittn

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Comments

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Well, as you will see, your regex is incorrect:

.*"status:\s"422.*
         ^ (look here)

.* matches any string before what follows.
"status:\ " matches literally the sequence of double quotes, the word status, ... beeep (there's a double quote after status, not after the colon and the next space character).

NOTE

Response object is not a POJO (pojo stands for the acronym (P)lain (O)ld (J)ava (O)bject, and what you are posting is, indeed, a JSON encoded string data)

The correct regexp should be (as the data shows):

"status":\s*(\d+),
       ^ (see how we moved the double quotes here)

The .* is not necessary, as any regexp that has no anchor char (^ at the beginning, or $ at the end) matches at any position in the string.
Then follows the string "status": literally.
Then a group \s* of spaces (indeed, tab or spaces, any number, even zero is valid)
Then a group of one or more digits (the parenthesis makes the subexpression to become a group, so you can select only the part matching that group, and get the status value)
Finally, the , comma after all, as everytime the status will be followed by a comma to separate the next field.

See demo.

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Aug 30, 2019 at 13:45

Luis Colorado

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2 Comments

amittn Over a year ago

nice one, just a small amendment "status":\s*422, So that it only checks for 422 response not any number.

Luis Colorado Over a year ago

Sorry, I didn't know... but include the comma, as not doing could include a number like 4223.

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