php unset array from 2d session array

Question

i am adding stuff to a 2d array like this:

 $_SESSION['vehicles'][] = array ('model' => $_REQUEST['blah1'], 'price' => $_REQUEST['blah2'], 'year' => $_REQUEST['blah3']);

how would i remove all arrays from the session that have a 'model' = to a variable of my choice? (note: there will always be many arrays in the session with the same model.)

i have tried the below but it doesn't seem to remove anything from my session array:

$model = "toyota";
foreach ($_SESSION['vehicles'] as $vehicle) 
{
    unset($vehicle[$model]);
}

Thanks!

Bil · Accepted Answer · 2011-04-25 12:14:50Z

5

$vehicle is passed by copy, so, unset $vehicle do nothing

$model = "toyota";
foreach ($_SESSION['vehicles'] as $idx => $vehicle){
    if($vehicle['model'] == $model){
        unset($_SESSION['vehicles'][$idx]);
    }
}

answered Apr 25, 2011 at 12:14

Bil

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Comments

deceze · Accepted Answer · 2011-04-25 12:28:04Z

5

$model = 'toyota';

// PHP <= 5.2
$_SESSION['vehicles'] = array_filter($_SESSION['vehicles'],
              create_function('$v', "return \$v['model'] != '$model';"));

// PHP 5.3+
$_SESSION['vehicles'] = array_filter($_SESSION['vehicles'],
              function ($v) use ($model) { return $v['model'] != $model; });

Or, your approach:

foreach ($_SESSION['vehicles'] as $key => $vehicle) {
    if ($vehicle['model'] == $model) {
        unset($_SESSION['vehicles'][$key]);
    }
}

edited Apr 25, 2011 at 12:28

answered Apr 25, 2011 at 12:15

deceze♦

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2 Comments

NikiC Over a year ago

Is the last code snipped undefined behavior (that works, but per se is undefined) or is unsetting keys in an array you currently iterator okay? +1

deceze Over a year ago

@nikic It works perfectly fine, foreach works on a copy of the array.

Pascal MARTIN · Accepted Answer · 2011-04-25 12:15:11Z

4

You have to :

iterate over your vehicles
for each vehicle, test if its model is the one you are looking for
and if yes, delete it :

Which could be translated by a portion of code like this one :

$model = "toyota";
foreach ($_SESSION['vehicles'] as $key => $vehicle) 
{
    if ($vehicle['model'] == $model) {
        // The current vehicle's model is what you are searching for
        // => delete if from $_SESSION
        unset($_SESSION['vehicles'][$key]);
    }
}

answered Apr 25, 2011 at 12:15

Pascal MARTIN

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Comments

score 3 · Accepted Answer · 2011-04-25 12:21:25Z

3

foreach($_SESSION['vehicles'] as $key => $vehicle) {
    if($vehicle['model'] == "toyota") {
        unset($_SESSION['vehicles'][$key]);
    }
}

Should do it.

I need to write my answers faster.

edited Apr 25, 2011 at 12:21

answered Apr 25, 2011 at 12:20

delete me

Comments

naiquevin · Accepted Answer · 2011-04-25 12:16:42Z

2

what you are trying to remove is $vehicle['toyota'] which is not present in the arrays

try this instead ..

$model = "toyota";
foreach ($_SESSION['vehicles'] as $key=>$vehicle) 
{
    if($model == $vehicle['model']) {
         unset($_SESSION['vehicles'][$key]);
    }    
}

answered Apr 25, 2011 at 12:16

naiquevin

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Comments

kwarunek · Accepted Answer · 2011-04-25 12:22:12Z

0

At first note that $_SESSION['vehicles'] is a numbered array, so $vehicle[$model] just can't work. Next to modify item in the foreach loop:

As of PHP 5, you can easily modify array's elements by preceding $value with &. This will assign reference instead of copying the value.

$model = "toyota";
foreach ($_SESSION['vehicles'] as &$vehicle) 
{
    if ($vehicle['model'] == $model)
         unset($vehicle);
}

answered Apr 25, 2011 at 12:22

kwarunek

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1 Comment

delete me Over a year ago

when he's doing &$vehicle instead of just $vehicle hes working on the actual element, not a copy.

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