Structure for storing string values in two-dimensional list in Python

Question

I need to create a matrix-like structure which can be accessed by its names of the columns and rows.

'''
           Misalign    CPU     Ret
LU_factor   0           6       21
Random      2           10      5
'''

row=["LU_factor","Random"]
col=['Misalign', 'CPU', 'Ret']
Total=[['0', '6', '21'],['2', '10', '5']]

for i in range(0,len(Total)):
    for j in range(0,len(Total[i])):
        print(Total[i][j],end=" ")
        # Matrix[row[i]][col[j]] =Total[i][j]

#print(Matrix)

I do not know what format or data structure I should use to store above data such that I could able to access like:

Matrix["LU_factor"]["CPU"] =6
Matrix["Random"]["Ret"] = 5

I have found one solution through numpy structured array, but I am looking for the solution without using numpy. Thanks in advance.

FabioL · Accepted Answer · 2019-09-18 12:17:42Z

4

You can use dictionaries of dictionaries, something like:

M = {"LU_factor": {'Misalign': 0, 'CPU': 6, 'Ret': 21}, 'Random': {'Misalign': 2, 'CPU': 10, 'Ret': 5}}

should works, you can access or assign values respectively with M["LU_factor"]["CPU"] and M["LU_factor"]["CPU"] = 5.

Specifically you can build the structure you need with a dict comprehension, using your example:

row=["LU_factor","Random"]
col=['Misalign', 'CPU', 'Ret']
Total=[['0', '6', '21'],['2', '10', '5']]

M = {r:{c:Total[k][i] for i, c in enumerate(col)} for k, r in enumerate(row)}

edited Sep 18, 2019 at 12:17

answered Sep 18, 2019 at 12:11

FabioL

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