parsing strings with Parse package

Question

I am attempting to create a program with a console input and parse the text input.

import parse


while True:

    def parse_text(text: str) -> str:
        result = parse.parse(text)
        return str(result)

    answer = input('Which type of component do you need help with, an AHU or VAV?')
    name = parse_text(answer)
    if {name} == 'VAV':
        print('Ok, what VAV number?')
    if {name} == 'AHU':
        print('Ok, what AHU number?')
    else:
        print('Please specify AHU or VAV')

I have a feeling the function parse_text isnt returning a string, can someone give me a tip?

Python 3.6.8 (tags/v3.6.8:3c6b436a57, Dec 24 2018, 00:16:47) [MSC v.1916 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license()" for more information.
>>> 
========== RESTART: C:/Users/benb/Desktop/text_parse/parse_hvac.py ==========
Which type of component do you need help with, an AHU or VAV?AHU
Traceback (most recent call last):
  File "C:/Users/benb/Desktop/text_parse/parse_hvac.py", line 13, in <module>
    name = parse_text(answer)
  File "C:/Users/benb/Desktop/text_parse/parse_hvac.py", line 9, in parse_text
    result = parse.parse(text)
TypeError: parse() missing 1 required positional argument: 'string'
>>>

there's so many syntax errors it doesn't even look like python — SuperStew
– SuperStew, Commented Sep 25, 2019 at 13:44
parse_text(text: str) -> str and {name}, and while not incorrect, str(result) is unnecessary — SuperStew
– SuperStew, Commented Sep 25, 2019 at 13:48
The first one is part of the type hints added in 3.5. But {name}.. I don't know what it is. — luis.parravicini
– luis.parravicini, Commented Sep 25, 2019 at 13:51
@SuperStew those are called function annotations and they are valid. Read more at python.org/dev/peps/pep-3107 — Robert Kearns
– Robert Kearns, Commented Sep 25, 2019 at 13:51

luis.parravicini · Accepted Answer · 2019-09-25 18:07:56Z

1

parse needs two arguments, look at https://github.com/r1chardj0n3s/parse

If the input function you call is the one provided by Python, why don't you just do

name = answer.upper()
if name == 'VAV':
    print('Ok, what VAV number?')

edited Sep 25, 2019 at 18:07

answered Sep 25, 2019 at 13:45

luis.parravicini

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4 Comments

bbartling Over a year ago

Thanks for the link, can you expand or post answer how to fix the issue? Sorry still learning...

luis.parravicini Over a year ago

See the edited answer. Also, what's the purpose of those curly braces in {name}?

bbartling Over a year ago

That worked, the curly brackets were from documentation I was trying to follow.

bbartling Over a year ago

One thing that sort of sucks the program loops thru to the very beginning..

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