How do I create a function for two-dimensional array search?

Question

please help me, I have a function to search for one-dimensional arrays, here are the source codes and their variables:

var fruits= ["Apple","Banana","Grape","Orange"];

function searchStringInArray (src1,fruits) 
{
  var res=""
  for (var j=0; j<src1.length; j++) {
    if (src1[j].match (searched)) 
    {
    res=res+src1[j]+","
    }
}
    return res;
} 
alert(searchStringInArray (src1,'Grape'));

but I want to modify the function to search for multidimensional arrays, with the following variables:

var fruits= [
    ["001","Apple","For John"],[["002","Banana","For Stuart"],["003","Grape","For Collins"],["004","Orange","For Ben"]
    ];

Approximately how the function is suitable for the variable?

If you want to continue the same code only then you have to put 1 more loop to process multi array. — Saima Haji
– Saima Haji, Commented Nov 5, 2019 at 7:09
@AnkitPandey I think it's supposed to be the fruits array. — Aadit M Shah
– Aadit M Shah, Commented Nov 5, 2019 at 7:18
oh sorry, it should be: alert (searchStringInArray (fruits, 'Grape')) — Benz Iskan
– Benz Iskan, Commented Nov 5, 2019 at 7:19

Ankit Pandey · Accepted Answer · 2019-11-05 07:40:24Z

1

A more convenient way to use this with the prototype.

const fruits = [
  ["001", "Apple", "For John"],
  ["002", "Banana", "For Stuart"],
  ["003", "Grape", "For Collins"],
  ["004", "Orange", "For Ben"]
]

Array.prototype.searchIn2DArray = function(fruitsName){
  let searched = false;
  for(let j=0; j<this.length; j++){
    if(this[j].indexOf(fruitsName) > -1){
      return this[j];
    }
  }
  return searched;
}

console.log(fruits.searchIn2DArray('Orange'));

answered Nov 5, 2019 at 7:40

Ankit Pandey

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2 Comments

user1945782 Over a year ago

Really, this isn't the best way to perform the operation; you should be using something like filter or find. If you're going to do it manually, then try a binary approach to the test, so you're not looking at every single element.

Ankit Pandey Over a year ago

@Paul, Thanks for the comment. But I am looking at all elements till not found.

Yosvel Quintero · Accepted Answer · 2019-11-05 09:36:26Z

1

You can use Array.prototype.find() combined with Array.prototype.includes():

const fruits = [
  ["001", "Apple", "For John"],
  ["002", "Banana", "For Stuart"],
  ["003", "Grape", "For Collins"],
  ["004", "Orange", "For Ben"]
]

const searchStringInArray = (src1, searched) => src1.find(arr => arr.includes(searched))
  
console.log(searchStringInArray(fruits, 'Grape'))

edited Nov 5, 2019 at 9:36

answered Nov 5, 2019 at 7:19

Yosvel Quintero

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Comments

Saima Haji · Accepted Answer · 2019-11-05 07:25:32Z

0

for(f of fruits){data=f.filter(s => s==="Apple").length > 0;
console.log(data); if(data){console.log("found");filteredD.push(f);}}

answered Nov 5, 2019 at 7:25

Saima Haji

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Comments

StepUp · Accepted Answer · 2019-11-05 07:33:15Z

0

It is possible to flat your multidimensional array and then find desired item:

const fruits= [
    ["001","Apple","For John"]
    ,[
        ["002","Banana","For Stuart"],
        ["003","Grape","For Collins"],
        ["004","Orange","For Ben"]
    ]
];

const flatArray = (arr) => {
    return arr.reduce(function (flat, toFlatten) {
      return flat.concat(Array.isArray(toFlatten) ? flatArray(toFlatten) : toFlatten);
    }, []);
  }

const flattened = flatArray(fruits);
const fruitToFind = 'Grape';
const result = flattened.find(f=> f === fruitToFind);
console.log(result);

answered Nov 5, 2019 at 7:33

StepUp

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