I'm trying to create a string on a list from a string
It looks like
#My list
list_ = ['a, b, c, d', 'f, g, h, i', 'j, k, l, m', 'n, o, p, q']
#Output that I'm looking for
['a', 'b', 'c', 'd', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q']
I got it from my code
for row in reader:
key = row[0]
pairs_dict[key] = row[1:]
getlist = pairs_list.append(f"{key}, {', '.join(pairs_dict[key])}")
#pairs_dict is dictionary and pairs_list is empty list
Try to do it using split() like this -
list_ = ['a, b, c, d', 'f, g, h, i', 'j, k, l, m', 'n, o, p, q']
result = []
for r in list_:
result.extend(r.split(', '))
print(result)
You could just use use str.join on the list and do a list comprehension or use re.split after the joining the list like,
>>> list_
['a, b, c, d', 'f, g, h, i', 'j, k, l, m', 'n, o, p, q']
>>> [x.strip() for x in ','.join(list_).split(',')]
['a', 'b', 'c', 'd', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q']
Or
>>> import re
>>> list_
['a, b, c, d', 'f, g, h, i', 'j, k, l, m', 'n, o, p, q']
>>> re.split(r',\s*', ','.join(list_)) # split on ',' followed by 0 or more space
['a', 'b', 'c', 'd', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q']
Maybe not the fatest solution but it works:
list_ = list(''.join(list_).replace(', ', ''))
