I need to assign a variable $x value that returns from the command 'file' on $1.
my code is:
echo $1 | xargs file 'x=$'
and the last part x=$ does not work.
I need that if the argument $1 is 'archive.zip' then the variable x will get the value of the command 'file' on it.
How can I do that?
Assign value to a variable in shell script is like below
a=$(echo $1 | xargs file)
The above means that execute what is inside $(...) and the output will be assigned to a variable with name a
Access contents of variable a
echo $a
You can execute also directly the file command with argument the file name and then store the output to a variable.
$1 is a special argument and its the first argument that used to call a script.
Example1:
root@server[/root] > echo wiki.20191206.tar.gz | xargs file
wiki.20191206.tar.gz: gzip compressed data, from Unix, last modified: Fri Dec 6 00:00:01 2019
root@server[/root] > a=$(echo wiki.20191206.tar.gz | xargs file)
root@server[/root] > echo $a
wiki.20191206.tar.gz: gzip compressed data, from Unix, last modified: Fri Dec 6 00:00:01 2019
Example2:
root@server[/root] > file wiki.20191206.tar.gz
wiki.20191206.tar.gz: gzip compressed data, from Unix, last modified: Fri Dec 6 00:00:01 2019
root@server[/root] > a=$(file wiki.20191206.tar.gz)
root@server[/root] > echo $a
wiki.20191206.tar.gz: gzip compressed data, from Unix, last modified: Fri Dec 6 00:00:01 201
x=$(file $1)