How to make a "while" loop using input from user?

Question

Currently using 3.8.1.

I was wondering how I could make a while True: loop like in the example below, but using a number that the user inputted instead of a word (for example any number equal to or lower then 100 would print something different. I've looked on this website, but I couldn't understand the answers for questions similar to mine.

while True:
    question = input("Would you like to save?")
    if question.lower() in ('yes'):
        print("Saved!")
        print("Select another option to continue.")
        break
    if question.lower() in ('no'):
        print ("Select another option to continue.")
        break
    else:
        print("Invalid answer. Please try yes or no.")

('yes') is not a tuple with one element; it's just a parenthesized string expression. ... in ('yes',) would do you want you expect, but there's no reason to use in with a hard-coded single-element container: just use question.lower() == 'yes'. — chepner
– chepner, Commented Feb 3, 2020 at 20:38
Does this answer your question? Asking the user for input until they give a valid response — Tomerikoo
– Tomerikoo, Commented Feb 3, 2020 at 20:48

Daniel · Accepted Answer · 2020-02-03 20:39:01Z

1

How about including less than / great than clauses in your if statements?

while True:

    # get user input:
    user_input = input("Would you like to save? ")

    # convert to int:
    number = int(user_input)

    if number <= 100:
        print("Saved!")
        print("Select another option to continue.")
        break
    elif number > 100:
        print ("Select another option to continue.")
        break
    else:
        print("Invalid answer. Please try yes or no.")

answered Feb 3, 2020 at 20:39

Daniel

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Comments

Cryptoharf84 · Accepted Answer · 2020-02-03 20:43:33Z

1

you need to extract the number from the input and then run your conditional evaluation of the inputed value.

while True:
        input_val = input("Enter a #?")
        try:
            num=int(input_val)
        except ValueError:
            print("You have entered an invalid number. please try again")
            continue

        if num == 1:
            print("bla bla")
        elif num ==2:
            print("bla bla 2")
        else:
            ...

edited Feb 3, 2020 at 20:43

answered Feb 3, 2020 at 20:39

Cryptoharf84

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snnguyen · Accepted Answer · 2020-02-03 20:44:10Z

0

input takes the user's input and outputs a string. To do something with numbers, check if the string is numeric, cast it to an int and do whatever you want

while True:
    answer = input("How many dogs do you have?")
    if answer.isnumeric():
        num_dogs = int(answer)
    else:
        print("Please input a valid number")

answered Feb 3, 2020 at 20:44

snnguyen

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Comments

Reyansh · Accepted Answer · 2020-02-03 20:55:21Z

0

I think you maybe want a list instead of a tuple.

Could this work:

while True:
    number = input("Enter a number?")
    if int(number) in list(n for n in range(100)):
            print("lower!")
    elif int(number) in [100]:
            print ("exact")
    else:
            print("higher")

answered Feb 3, 2020 at 20:55

Reyansh

1

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