function test{
for($a=0;$a -le 2;$a++){
if($a -eq 1){break}
}
}
#----outside----
write-output $a
How to call a variable from a function and not to use return to get $a ?
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2 Answers
Aside from using scopes as described in Rob's answer, there is also the possibility to send a parameter by reference.
This means that inside the function, a reference to the original variable is used, so whatever the function does with it, the original value is affected.
The downside is that when using references, you must use the Value property of the System.Management.Automation.PSReference type to access/alter your data as in the example below:
function test ([ref]$a) {
for ($a.Value = 0; $a.Value -le 2; $a.Value++){
if ($a.Value -eq 1) {break}
}
}
#----outside----
$a = 0
test ([ref]$a) # the parameter needs to be wrapped inside brackets and prefixed by [ref]
Write-Output $a
When sending a parameter that is an object type, like for instance a Hashtable, then by default it is always passed to the function by reference and for those you don't use the [ref] accellerator.
Comments
Have you tried to set the variable global?
$var="Test"
function test()
{
$global:var="blub"
}
test
$var
or
$a = 0
function test{
for($global:a=0;$global:a -le 2;$global:a++){
if($global:a -eq 1){break}
}
}
test
write-output $a
1 Comment
Theo
The script scope will be enough I gather.