I am trying to get the search data from an API in angular 8. I have a problem with method response.json() as it creates an error response.json is not a function.
search(query: string): Observable<SResult[]> {
const queryUrl = `${url}${params}`;
return this.http.get(queryUrl, {headers})
.pipe(
map((response : any) => {
return (<any>response.json())
.map((res) => {
return new SearchResult(res)
})
})
)
}
When using angular HttpClient your request is automatically parsed as JSON (unless the request's response type is not set to handle different data type). As @Alexander Statoselsky said in the comment, you can set the type of your response, so TypeScript will now what data structure is returned from the backend.
search(query: string): Observable<SearchResult[]> {
const queryUrl = `${url}${params}`;
return this.http.get<CustomResultInterface[]>(queryUrl, {headers}).pipe(
// As HttpClient cares only about the structure, you still need to loop
// through the returned data and create a classes if you want the method to return
// a list of SearchResult classes.
// CustomResultInterface is your custom interface that carries only the structure of the response
map(results => results.map(result => new SearchResult(result)))
);
}
Also, when using queryParameters, you might want to take a look at HttpParams which you'd use as following example
search(query: string): Observable<SearchResult[]> {
const params = new HttpParams();
params.set('query', query);
return this.http.get<CustomResultInterface[]>(url, { params, headers }).pipe(
map(results => results.map(result => new SearchResult(result)))
);
}
response.json(). Instead just make it a typed response