Filter array of objects if object contains attribute with value present in another array

Question

I have the following array of objects.

const abc = [
      {
        sku: 1,
        features: ["Slim"],
        fields: [
          { label: "Material", value: "Material1" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 2,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material2" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 3,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material3" },
          { label: "Type", value: "Type2" },
        ]
      }
    ];

I want to filter only those objects whose features and fields value are present in this

const fieldsArr = ["Material1", "Material2", "Type1", "Slim"]

Expected Output is

let output = [
      {
        sku: 1,
        features: ["Slim"],
        fields: [
          { label: "Material", value: "Material1" },
          { label: "Type", value: "Type1" },
        ]
      },
      {
        sku: 2,
        features: ["Cotton"],
        fields: [
          { label: "Material", value: "Material2" },
          { label: "Type", value: "Type1" },
        ]
      },
    ]

I solved the features part like this

abc.forEach(e => {
      if (e.features.some(v => fieldsArr.indexOf(v) !== -1)) {
        output.push(e);
      }
    });

But I'm having problem with filtering the fields part. Is there a way to filter the objects based on the above condition in an optimized way.

Why do you use forEach and push when you can use filter? — Christian Vincenzo Traina
– Christian Vincenzo Traina, Commented Mar 11, 2020 at 9:54

Nina Scholz · Accepted Answer · 2020-03-11 09:54:03Z

7

You need to iterate the nested arrays as well.

const
    abc = [{ sku: 1, features: ["Slim"], fields: [{ label: "Material", value: "Material1" }, { label: "Type", value: "Type1" }] }, { sku: 2, features: ["Cotton"], fields: [{ label: "Material", value: "Material2" }, { label: "Type", value: "Type1" }] }, { sku: 3, features: ["Cotton"], fields: [{ label: "Material", value: "Material3" }, { label: "Type", value: "Type2" }] }],        fieldsArr = ["Material1", "Material2", "Type1", "Slim"],
    result = abc.filter(({ features, fields }) =>
        features.some(v => fieldsArr.includes(v)) ||
        fields.some(({ value }) => fieldsArr.includes(value))
    );

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Mar 11, 2020 at 9:54

Nina Scholz

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Comments

Siva Kondapi Venkata · Accepted Answer · 2020-03-11 10:33:03Z

2

Use filter, and check each items combined values of features and fields (value) with fieldsArr.

const abc = [
  {
    sku: 1,
    features: ["Slim"],
    fields: [
      { label: "Material", value: "Material1" },
      { label: "Type", value: "Type1" }
    ]
  },
  {
    sku: 2,
    features: ["Cotton"],
    fields: [
      { label: "Material", value: "Material2" },
      { label: "Type", value: "Type1" }
    ]
  },
  {
    sku: 3,
    features: ["Cotton"],
    fields: [
      { label: "Material", value: "Material3" },
      { label: "Type", value: "Type2" }
    ]
  }
];

const fieldsArr = ["Material1", "Material2", "Type1", "Slim"];

const res = abc.filter(item =>
  [...item.features, ...item.fields.map(x => x.value)].some(fea =>
    fieldsArr.includes(fea)
  )
);

console.log(res);

// Update: more concise using destructure
const res2 = abc.filter(({features, fields}) =>
  [...features, ...fields.map(({value}) => value)].some(fea =>
    fieldsArr.includes(fea)
  )
);
console.log(res2);

edited Mar 11, 2020 at 10:33

answered Mar 11, 2020 at 10:09

Siva Kondapi Venkata

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1 Comment

Siva Kondapi Venkata Over a year ago

np! @YogeshKudikala, Check out now.

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