Typescript: define type with keys from other type

Question

Suppose you have this Typescript class:

class Person {
  name: string;
  age: number;
}

How would I declare an object type that has the same properties, but any type, but for which all properties are optional? Here are some possible values that should be compatible with that type:

data = {};
data = {name: 'John'};
data = {name: anyValue};
data = {age: 'can be a string'}
data = {name: anyValue, age: null};

I'm not even sure what to search for. I've tried something like this:

let data: {(keyof Person): any};

But that does not compile

Shayan Toqraee · Accepted Answer · 2020-03-21 18:29:37Z

8

Your last try is almost correct!

let data: { [k in keyof Person]: any };

answered Mar 21, 2020 at 18:29

Shayan Toqraee

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1 Comment

Shayan Toqraee Over a year ago

When writing complex types, I always write let test: ReadOnly<any>; somewhere and use "Go to Type Definition" on ReadOnly to get to typescript's own types library and look at the types defined there.

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