Is it possible to insert a python list to np array?

Question

My goal is for nd_array[0] = 1,2,3,4,5 I have sat on this problem for hours now. I have attempted to create the whole 2D list as a list and then using np.asarray(just creates the strangiest array i havbe ever seen, not even sure how to explain it) , I've tried np.append this is just a cut out from a different problem. In the actual example, I am looping and creating a list with 5 values, then adding those values to nparray[0] then the loop after adding to nparray[1]


nd_array = np.zeros(shape=(5, 5))

pyth_list = [1, 2, 3, 4, 5]

np.insert(nd_array, pyth_list, 0)


print(123)

np.insert(nd_array, pyth_list, 0) this obviously doesn't do anything since np.insert doesn't mutate inplace, but instead returns a new array. I also don't know what this print(123) has to do with anything? — ruohola
– ruohola, Commented Mar 24, 2020 at 14:56
The way I normally figure out how something works in programming, especially in small extracted programs like these, is to use the debugger and inspect how elements change. the final line means that it wont finish the debugging once i click F8 after the np.insert() line and also lets me put a breakpoint there to inspect faster without having to click F8 @ruohola — Marius Kuzm
– Marius Kuzm, Commented Mar 24, 2020 at 18:00

kederrac · Accepted Answer · 2020-03-24 14:56:57Z

1

you can use:

nd_array[0] = [1, 2, 3, 4, 5]
nd_array

output:

array([[1., 2., 3., 4., 5.],
       [0., 0., 0., 0., 0.],
       [0., 0., 0., 0., 0.],
       [0., 0., 0., 0., 0.],
       [0., 0., 0., 0., 0.]])

answered Mar 24, 2020 at 14:56

kederrac

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1 Comment

Marius Kuzm Over a year ago

it's just that easy. 1-2hours well spent

Omar Atef · Accepted Answer · 2020-03-24 14:59:18Z

0

You can use vstack()

nd_array = np.zeros(shape=(5, 5))

pyth_list = [1, 2, 3, 4, 5]

np.vstack([pyth_list,nd_array])

answered Mar 24, 2020 at 14:59

Omar Atef

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ruohola · Accepted Answer · 2020-03-24 15:07:55Z

0

Yes you can, it's as simple as:

import numpy as np

nd_array = np.zeros(shape=(5, 5))
pyth_list = [1, 2, 3, 4, 5]

nd_array[0] = pyth_list
print(nd_array)

Output:

[[1. 2. 3. 4. 5.]
 [0. 0. 0. 0. 0.]
 [0. 0. 0. 0. 0.]
 [0. 0. 0. 0. 0.]
 [0. 0. 0. 0. 0.]]

edited Mar 24, 2020 at 15:07

answered Mar 24, 2020 at 14:57

ruohola

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