different type of 2d array in Python

Question

I have this line that build a 2d array

ResultsArray = multilabel_binarizer.transform(results_df['result'])

when I get ResultsArray values I get this

ResultsArray
Out[104]: 
array([[0, 0, 0, ..., 0, 0, 1],
       [0, 0, 0, ..., 0, 0, 1],
       [0, 0, 0, ..., 0, 0, 1],
       ...,
       [0, 0, 0, ..., 0, 0, 1],
       [0, 1, 0, ..., 0, 0, 1],
       [0, 0, 0, ..., 0, 0, 1]])

When I try to build my own 2d array like this

a = [["A1","A2","A3"],["B1","B2","B3"],["C1","C2","C3"]]

a
Out[123]: [['A1', 'A2', 'A3'], ['B1', 'B2', 'B3'], ['C1', 'C2', 'C3']]

when I do the shape of the ResultsArray

ResultsArray.shape
Out[126]: (999, 25)

but for my array a

I get error

a.shape

Traceback (most recent call last):

  File "<ipython-input-127-d6da0fa94082>", line 1, in <module>
    a.shape

AttributeError: 'list' object has no attribute 'shape'

how to create an 2d array that has same properties as ResultsArray

Does this answer your question? 'list' object has no attribute 'shape' — dspencer
– dspencer, Commented Mar 30, 2020 at 6:18

hmhmmm · Accepted Answer · 2020-03-30 05:45:34Z

2

That's because what you're creating is a Python's list which does not have the shape attribute, while multilabel_binarizer.transform returns a numpy.array.

You can wrap your list in numpy.array to make it the same:

import numpy

a = numpy.array([["A1","A2","A3"],["B1","B2","B3"],["C1","C2","C3"]])
a.shape

answered Mar 30, 2020 at 5:45

hmhmmm

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