Storing String Output of SED Commnd in an Array In Shell Script

Question

I have an XML file of the format:

<classes>

 <subject lb="Fall Sem 2020">
  <name>Operating System</name>
  <credit>3</credit>
  <type>Theory</type>
  <faculty>Prof. XYZ</faculty> 
 </subject>

 <subject lb="Spring Sem 2020">
  <name>Web Development</name>
  <credit>3</credit>
  <type>Lab</type>
 </subject>

 <subject lb="Fall Sem 2021">
  <name>Computer Network</name>
  <credit>3</credit>
  <type>Theory</type>
  <faculty>Prof. ABC</faculty> 
 </subject>

 <subject lb="Spring Sem 2021">
  <name>Software Engineering</name>
  <credit>3</credit>
  <type>Lab</type>
 </subject>

</classes>

I'm able to get the desired result using sed command. i.e. sed -En 's/.* lb="([^"]+)".*/\1/p' file

Output:

Fall Sem 2020
Spring Sem 2020
Fall Sem 2021
Spring Sem 2021

I want this output to be stored in an array. i.e.

arr[0]="Fall Sem 2020"

My try: arr=($(sed -En 's/.* lb="([^"]+)".*/\1/p' file)) But in this case, I'm getting individual element as an array element. i.e. arr[0]="Fall"

Check this thread --> stackoverflow.com/questions/24628076/… — Digvijay S
– Digvijay S, Commented Apr 15, 2020 at 12:43
The best answer in that Q&A is the last one using readarray, I'd say. — Benjamin W.
– Benjamin W., Commented Apr 15, 2020 at 12:47

RavinderSingh13 · Accepted Answer · 2020-04-15 12:55:02Z

1

Could you please try following(considering that OP doesn't have xml tools and can't install them too).

IFS=',';array=( $(
awk '
BEGIN{ OFS="," }
/<subject lb="/{
  match($0,/".*"/)
  val=(val?val OFS:"")substr($0,RSTART+1,RLENGTH-2)
}
END{
  print val
}' Input_file))

To print all elements of array use:

echo ${array[@]}
Fall Sem 2020 Spring Sem 2020 Fall Sem 2021 Spring Sem 2021

To print specific element use:

echo ${array[0]}
Fall Sem 2020

edited Apr 15, 2020 at 12:55

answered Apr 15, 2020 at 12:49

RavinderSingh13

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Cyrus · Accepted Answer · 2020-04-15 12:47:57Z

1

With bash:

# disable job control and enable lastpipe to run mapfile in current environment
set +m; shopt -s lastpipe

sed -En 's/.* lb="([^"]+)".*/\1/p' file | mapfile -t arr

declare -p arr

Output:

declare -a arr=([0]="Fall Sem 2020" [1]="Spring Sem 2020" [2]="Fall Sem 2021" [3]="Spring Sem 2021")

In a script job control is disabled by default.

answered Apr 15, 2020 at 12:47

Cyrus

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Comments

Benjamin W. · Accepted Answer · 2020-04-15 12:56:05Z

0

You could use an XML aware tool such as XmlStarlet to extract the attribute you want, and then use readarray and process substitution to read the output into an array:

$ readarray -t arr < <(xml sel -t -v 'classes/subject/@lb' infile.xml)
$ declare -p arr
declare -a arr=([0]="Fall Sem 2020" [1]="Spring Sem 2020" [2]="Fall Sem 2021" [3]="Spring Sem 2021")

answered Apr 15, 2020 at 12:56

Benjamin W.

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