I am looking for a solution to compare two instances of an Oject so instead of
list.sort((a, b) => (a.number > b.number) ? 1 : -1)
I can have simply have list.sort()
Is it possible ?
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2 Answers
The doc say that in arr.sort([compareFunction]), if compareFunction is omitted, the array elements are converted to strings, then sorted according to each character's Unicode code point value, so it's not suited for a list of object.
But really, you should stick to precising a compare function, sorting by object key is really not verbose:
const arr = [
{ number: 10 },
{ number: 20 },
{ number: 0 },
{ number: 30 },
]
arr.sort((a,b) => a.number - b.number)
console.log(arr)
Comments
let arr = [2,56,12,89,21]
arr.sort(function(a, b){return a-b});did you try this one? because we should always return a+b or a-b in sort method otherwise this will not effectable i think
2 Comments
CitizenFiftyTwo
This is an array of primitive number. What I am looking for is a way to sort an array, Object like so : let arr = [{number:2},{number: 56},{number:12},{number:89},{number:21}]
arslan
ohh ok then wrap this in foreach methodand push values of numbers in any array then try sort