Adding two integers of a double digit integer in Javascript

Question

I was attempting a coding practice where I had to take a two digit integer, split the integer into its two digits and add those digits.

function addTwoDigits(n) {
var n = n
var string = n.toString()
var split = string.split("")
var integer= split.map(Number)
var z = integer[0]+integer[1]
console.log(z)

}

The output of my code was correct on each of the tests, but the code checks still failed. If anyone can provide some insight into why, I would appreciate it.

How does the code check checks your code? Does it specify a specific type that your answer needs to be in? — Algo7
– Algo7, Commented Apr 21, 2020 at 21:46
You could do that in a single line function addTwoDigits(n) {return Math.floor(n/10) + (n%10));} — Cedric Cholley
– Cedric Cholley, Commented Apr 21, 2020 at 21:52
@CedricCholley Thank you that worked great, I definitely will have to look more into Math.floor — Jack Dempsey
– Jack Dempsey, Commented Apr 21, 2020 at 22:04
@AvivLo it checks my code against random double digit integers and sees if the output of my code matches the correct answers or expected output based on those values — Jack Dempsey
– Jack Dempsey, Commented Apr 21, 2020 at 22:05

Cedric Cholley · Accepted Answer · 2020-04-21 22:06:56Z

2

You could write the function this way

function addTwoDigits(n) {
    return Math.floor(n/10) + (n%10));
}

answered Apr 21, 2020 at 22:06

Cedric Cholley

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Comments

Aaron Boult · Accepted Answer · 2020-04-21 21:53:59Z

0

I have encountered a similar issue before. The solution for me was returning the value, rather than logging it to the console.

Instead of console.log(z) try return z

answered Apr 21, 2020 at 21:53

Aaron Boult

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Comments

KooiInc · Accepted Answer · 2020-04-24 09:11:47Z

0

Not sure what you mean by "but the code checks still failed". Here's a oneliner for n-digit numbers, using a reducer:

const sumOfIndividualDigits = n => 
  [...`${n}`]
  // ^ convert to Array of strings
  .map(Number)
  //   ^convert element (back) to Numbers
  .reduce( (acc, value) => acc + value, 0);
  //       ^ reduce to 1 value (sum)
  
console.log(sumOfIndividualDigits(22));
console.log(sumOfIndividualDigits(12345678));

edited Apr 24, 2020 at 9:11

answered Apr 21, 2020 at 21:57

KooiInc

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