Javascript push method

Question

What am I doing wrong here? my array is empty.

var infoarray = [{"address":"07288 Albertha Station","city":"Littelside","created_at":"2011-05-25T19:24:51Z","id":1,"name":"Mr. Emmitt Emmerich","state":"Missouri","updated_at":"2011-05-25T19:24:51Z","zip":"75475-9938"},{MORE INFO}]



 // Populates myarray from infoarray ruby object
      var myarray = new Array();
  $(document).ready(function(){

  $.each(infoarray,function(key,value){
    myarray.push(value['city'])
   });
  });
  console.log(myarray);

Works for me: jsfiddle.net/uqzjQ

mVChr
– mVChr

2011-05-26 21:16:15 +00:00
Commented May 26, 2011 at 21:16 — mVChr
– mVChr, Commented May 26, 2011 at 21:16

Raze · Accepted Answer · 2011-05-26 21:10:44Z

2

I don't think

InfoArray = var hotelinfo = [{"address":"07288 Albertha Station","city":"Littelside","created_at":"2011-05-25T19:24:51Z","id":1,"name":"Mr. Emmitt Emmerich","state":"Missouri","updated_at":"2011-05-25T19:24:51Z","zip":"75475-9938"},{MORE INFO}]

is valid JavaScript. You'll have to split it:

var hotelinfo;
InfoArray = hotelinfo = [{"address":"07288 Albertha Station","city":"Littelside","created_at":"2011-05-25T19:24:51Z","id":1,"name":"Mr. Emmitt Emmerich","state":"Missouri","updated_at":"2011-05-25T19:24:51Z","zip":"75475-9938"},{MORE INFO}]

answered May 26, 2011 at 21:10

Raze

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1 Comment

JZ. Over a year ago

This was an error in my transcription between my console and stackoverflow. The infoarray is already the same case as in the funciton. This is not working.

Metagrapher · Accepted Answer · 2011-05-26 21:09:48Z

1

javascript is case sensitive, so InfoArray and infoarray are different variables.

Does this work?:

var hotelinfo = [{"address":"07288 Albertha Station","city":"Littelside","created_at":"2011-05-25T19:24:51Z","id":1,"name":"Mr. Emmitt Emmerich","state":"Missouri","updated_at":"2011-05-25T19:24:51Z","zip":"75475-9938"},{MORE INFO}]

 // Populates myarray from infoarray ruby object
      var myarray = new Array();
  $(document).ready(function(){

  $.each(hotelinfo,function(key,value){
    myarray.push(value['city'])
   });
  });
  console.log(myarray);

answered May 26, 2011 at 21:09

Metagrapher

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Comments

amit_g · Accepted Answer · 2011-05-26 21:10:13Z

0

Javascript is case sensitive so use

$.each(InfoArray,function(key,value){

i.e. InforArray is not same as inforarray. Also the line

InfoArray = var hotelinfo =

should be

InfoArray = hotelinfo =

answered May 26, 2011 at 21:10

amit_g

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1 Comment

Metagrapher Over a year ago

another good point... it's invalid to declare a variable in the middle of an expression. The var keyword must be at the beginning of a line. It is perfectly valid to declare multiple variables in a single line, but the var keyword must be the first on the line.

Metagrapher · Accepted Answer · 2011-05-26 21:18:33Z

0

it's invalid to declare a variable in the middle of an expression. The var keyword must be at the beginning of a line. It is perfectly valid to declare multiple variables in a single line, but the var keyword must be the first on the line.

answered May 26, 2011 at 21:18

Metagrapher

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