0
for a in {P02183606,P02183608}
do
for b in {PID,PID2}
do
curl -i -H "Authorization:Token sample" "Content-type: application/json" -X GET "http://mastindia//project/push?applicationRefNo=$a&applicationFormId=$b"
done;
done;

Expected Output Service should call 2 times not 4 times.(Issue is only $a and $ b values should be below)

http://applicationRefNo=P02183606&applicationFormId=PID
http://applicationRefNo=P02183608&applicationFormId=PID2
1
  • 5
    It's probably a bad idea to post your authorization token in public. It's certainly not necessary for the question. Commented May 4, 2020 at 17:35

1 Answer 1

1

A nested for loop will always run n*n2 times.

In your case, there is no need to nest the loop, you can just do it like this:

#bin/bash
whatever=("P02183606" "PID" "P02183608" "PID2");
for((i = 0; i<${#whatever[@]}; i=i+2));
do
curl -i -H "Authorization:Token dont share it ffs" "Content-type: application/json" -X GET "http://indiafirstlife.com//onlineInsurance-rest/uploadDocument/uploadDocumentsOmniMannualPush?applicationRefNo=${whatever[i]}&applicationFormId=${whatever[i+1]}"
echo "Accessing: http://indiafirstlife.com/onlineInsurance-rest/uploadDocument/uploadDocumentsOmniMannualPush?applicationRefNo=${whatever[i]}&applicationFormId=${whatever[i+1]}"
done

Output:

Accessing: http://indiafirstlife.com/onlineInsurance-rest/uploadDocument/uploadDocumentsOmniMannualPush?applicationRefNo=P02183606&applicationFormId=PID
Accessing: http://indiafirstlife.com/onlineInsurance-rest/uploadDocument/uploadDocumentsOmniMannualPush?applicationRefNo=P02183608&applicationFormId=PID2
Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.