removing elements from an array - that DON'T appear in another array in PHP

Question

I have a function that receives an array as input. ("$inputArr")

the array has a white list of allowed elements it might contain. (specified an array called "$allowedArr").

I want to filter out any elements in the input array isn't in the white list of $allowedArr.

I need to keep the $allowedArr an array.

I know how do to this using a foreach loop (code bellow) but I was wondering if there is a built in function in PHP that can do this more efficiently. (without a loop) array_diff won't do because it does the opposite of what I'm trying to accomplish - because i'm not looking for what is different between the two array, but what's similar


$result = myFunc(array('red', 'green', 'yellow', 'blue'));

function myFunc(array $inputArr){
    $allowedArr = array('green', 'blue');
    $filteredArr = array();

    foreach ($inputArr as $inputElement){
        if(in_array($inputElement, $allowedArr)){
            array_push($filteredArr, $inputElement);
        }
    }

    return $filteredArr;
}

the result i'm trying to get is in this case is for $result to be:

array ('blue', 'green')

Yezan Rafed · Accepted Answer · 2020-05-05 16:18:06Z

3

Yes you can use the intersect built-in function:

$input = array('red', 'green', 'yellow', 'blue');

$whitelist = array('green', 'blue');

$filteredInput = array_intersect($input, $whitelist);

answered May 5, 2020 at 16:18

Yezan Rafed

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kamil.w · Accepted Answer · 2020-05-05 18:13:10Z

0

Looks simple for this type of structure and i think that you can simply use

$allowed = ['blue', 'green'];

$result = array_intersect(['blue','green','yellow','red'], $allowed);

edited May 5, 2020 at 18:13

answered May 5, 2020 at 16:22

kamil.w

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