How to return index of object element matched from a check array

Question

i hope the title is properly expressive of the problem i'm trying to solve. what i need to do is search an object for a matching element from a check array and return the object's index of that match. to whit:

const checkArray = ['18A38', '182B92', '85F33'];    //  these are the values to match
const dataOject = [
  0 => ['id'=>'853K83', 'isGO'=>false],             //  this is the object to search through
  1 => ['id'=>'85F33', 'isGO'=>true],
  2 => ['id'=>'97T223', 'isGO'=>true],
  3 => ['id'=>'18A38', 'isGO'=>false],
  4 => ['id'=>'182B92', 'isGO'=>true],
  ...
];

what i need to do is find the matching index so i can then check if the isGO flag is set. this is what i was trying when i dead-ended:

results = checkArray.forEach(function(value, index){
  if (dataObject.findIndex(function(k=> k == value))) results.push(k);
    //  i know 'results.push(k)' is not right, but it's the essence of what i want.  :P
};

what i am expecting is that results will be an array of indexes that i can then go back and check the dataObject for set isGO flags; results should look like this:

results = [3, 1, 4];

but i'm stumped on how to make the findIndex complete properly. i've read this and this and this but, while educational, they aren't dealing with an array and an object. i do have underscore in this project, but, again, haven't found anything that i comprehend as useful in this scenario.

how do i get this to run in a way that gives me what i need?

Assuming we fix the syntax of dataObject so it's a proper array storing proper objects: const results = checkArray.map(val => dataObject.findIndex(o => o.id == val)); — user5734311
– user5734311, Commented May 9, 2020 at 0:01
I just copy/paste from var_dump and tweak, bud. Sufficient to communicate the idea. At any rate, I'll give your suggestion a whirl. — WhiteRau
– WhiteRau, Commented May 9, 2020 at 0:23

Robo Robok · Accepted Answer · 2023-01-31 13:36:03Z

3

Instead of returning the indexes, isn't it easier to return the objects themselves?

const matchedObjects = dataObject.filter(
   ({ id }) => checkArray.includes(id)
);

That will return all objects having id found in your checkArray.

Having these objects in matchedObjects, you can iterate through them and do whatever you wish.

edited Jan 31, 2023 at 13:36

answered May 9, 2020 at 0:02

Robo Robok

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3 Comments

WhiteRau Over a year ago

uh...yeah... that's so damn obvious, I want to bash my head into the desk... 🤪

Robo Robok Over a year ago

Do it gently 😋

WhiteRau Over a year ago

lmao. thank you. this worked perfectly. more perfectly than i knew i needed, actually.

Mister Jojo · Accepted Answer · 2020-05-09 00:17:05Z

1

something like that ?

const checkArray = ['18A38', '182B92', '85F33'] 

const dataOject =
  [ { id:'853K83', isGo:false }
  , { id:'85F33',  isGo:true  }
  , { id:'97T223', isGo:true  }
  , { id:'18A38',  isGo:false }
  , { id:'182B92', isGo:true  }
  ];

const result = checkArray.map(val=>dataOject.findIndex(el=>el.id===val) )


console.log( JSON.stringify(result))

answered May 9, 2020 at 0:17

Mister Jojo

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2 Comments

WhiteRau Over a year ago

thank you. this is excellent. and it targets exactly the thing i was looking for.

WhiteRau Over a year ago

Weird. I did actually. Here, I clicked again. You do deserve the vote.

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