how can I define python class with list attribute and the class constructor that accept variable arguments?

Question

How can I define a python attribute as a class? I want to define a Python class that instantiate the objects that are list type. I can do that using __init__ and a class method, but I'm looking for a way to avoid using a method. Second question is that I'm wondering if I can define a class with a constructor that accept variable arguments (e.g. to use this class to instantiate objects with different No of indexes ([4,5,6] and [1,2,3,4,7]). I've copied my code below. Thanks for your help :)

    class SuperList(list):
        def __init__(self, a, b, c):
            self.a = a
            self.b = b
            self.c = c
        def My_list(self):
            return [self.a, self.b, self.c]
    obj1 = SuperList(1, 2, 3)
    List1 = obj1.My_list()
    List1.append(8)
    print(List1)

@Tomerikoo The SuperList class inherits from inbuilt <class 'list> and can be useful for creating custom methods without overwriting inbuilt class. — lorem_bacon
– lorem_bacon, Commented May 26, 2020 at 13:21

luigibertaco · Accepted Answer · 2020-05-26 03:54:55Z

1

I am not really sure what you are trying to achieve with the "class generated list" but find below one example that may give you a better understanding.

As you are inheriting from list, just by doing the following you would have a custom list implementation:

class SuperList(list):
    def __init__(self, *args):
        super().__init__(args)

list1 = SuperList(1, 2, 3)
list1.append(8)
print(list1)

list2 = SuperList(1, 2, 3, 7, 8, 9)
list2.append(999)
print(list2)

answered May 26, 2020 at 3:54

luigibertaco

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lorem_bacon · Accepted Answer · 2020-05-26 04:03:32Z

0


class SuperList(list):
    def __init__(self,*a):
        self.myList = list(a)
    def My_list(self):
        return self.myList

This works for multiple argument

obj1 = SuperList(1, 2, 54, 3)
print(obj1.My_list())

answered May 26, 2020 at 4:03

lorem_bacon

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