How do I sort this array?
Input: ['sfr2ta', '2ab', 'bbb1ddd']
Output: ['bbb1ddd', 'sfr2ta', '2ab']
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What is the criteria for sorting it that way?Abion47– Abion472020-06-21 03:42:45 +00:00Commented Jun 21, 2020 at 3:42
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string that contains letters in the first position will be prioritise first @Abion47lontonglah– lontonglah2020-06-21 03:49:35 +00:00Commented Jun 21, 2020 at 3:49
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Sorry, didn't fully read the question. In which way would you like to order your characters? The conventional ascii ordering puts "2" before "b" (as in, in JavaScript "2" < "b").yeerk– yeerk2020-06-21 03:58:51 +00:00Commented Jun 21, 2020 at 3:58
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How is sorting based on the first character different from sorting based on the whole strings? Do you want the sort to deliberately ignore everything except the first character?JLRishe– JLRishe2020-06-21 04:28:55 +00:00Commented Jun 21, 2020 at 4:28
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3 Answers
If you want to sort it by the first charachter then the output should be like this: ['2ab', 'bbb1ddd', 'sfr2ta'].
But if you want to sort it that letters come before nubmers, then you write something like:
l = ['sfr2ta', '2ab', 'bbb1ddd'];
lNums = []
lStrs = []
for( let s of l ) {
if(s[0] >= 0 && s[0] <= 9){
lNums.push(s);
}
else {
lStrs.push(s);
}
}
lNums.sort();
lStrs.sort();
l = lStrs.concat(lNums);
console.log(l)output: [ 'bbb1ddd', 'sfr2ta', '2ab' ]
Comments
Depending on how you want zero length strings to act (""), this should work:
function sortByFirstCharacter(arr) {
arr.sort((lhs, rhs) => {
if(lhs === rhs) return 0;
if(lhs === "") return -1;
if(rhs === "") return +1;
return (
lhs[0] < rhs[0] ? -1
: lhs[0] > rhs[0] ? +1
: 0
);
});
return arr;
}
1 Comment
lontonglah
thanks, but the string that contains letters in the first position needs to appear first. the code will put 2ab as the first
We can do this with sort:
var s = ['sfr2ta', '2ab', 'bbb1ddd'];
var result = [...s.filter(n=>!Number(n[0])).sort((a,b)=>a[0].localeCompare(b[0])), ...s.filter(p=>Number(p[0]))];
console.log(result);