Looking for a simple way to get a list of the worksheets in an Excel workbook using win32com in Python 3. I would prefer to avoid iterating, but can't find a function to do so.
1 Answer
- Callig the
.Sheetsproperty of the workbook, returns a Sheets collection,<win32com.gen_py.Microsoft Excel 16.0 Object Library.Sheets instance at 0x1597583762504>- In order to get each sheet, you must iterate, which returns an object,
<win32com.gen_py.Microsoft Excel 16.0 Object Library._Worksheet instance at 0x1597583219080>for each sheet. - To get the name of each sheet, you must use the
.Namemethod
- In order to get each sheet, you must iterate, which returns an object,
- As shown below, you can easily get
sheet_nameswith a list comprehension - Alternative, you can get a dictionary of worksheet objects with
ws = {f'ws{i}': wb.Sheets(sheet.Name) for i, sheet in enumerate(wb.Sheets)}- Assign a value with
ws['ws0'].Range('A1').Value = 1
Function
import win32com.client as win32
from pathlib import Path
import sys
win32c = win32.constants
def run_excel(f_path: Path, f_name: str) -> list:
filename = f_path / f_name
# create excel object
excel = win32.gencache.EnsureDispatch('Excel.Application')
# excel can be visible or not
excel.Visible = True # False
# try except for file / path
try:
wb = excel.Workbooks.Open(filename)
except com_error as e:
if e.excepinfo[5] == -2146827284:
print(f'Failed to open spreadsheet. Invalid filename or location: {filename}')
else:
raise e
sys.exit(1)
# get worksheet names
sheet_names = [sheet.Name for sheet in wb.Sheets]
wb.Close(True)
excel.Quit()
return sheet_names
Setup and function call
# file path
f_path = Path.cwd() # file in current working directory
# f_path = Path(r'c:\...\Documents') # file located somewhere else
# excel file
f_name = 'test.xlsx'
# function call
run_excel(f_path, f_name)
# output
['Sheet1', 'Sheet2', 'Sheet3', 'Sheet4']
# create a worksheet object
ws1 = wb.Sheets('Sheet1')