Python Selenium use elif with finding elements

Question

my current code is the following:

    buttons = driver.find_elements(By.XPATH, "...xpath")
    if len(buttons) > 0:
        for idx in range(len(buttons)):
            buttons[idx].send_keys('\n')
            res += 1
        time.sleep(1)
        driver.refresh()
    else:
        nxt = driver.find_element(By.CSS_SELECTOR, ".paging_bootstrap i.fa-angle-right.fa")
        driver.execute_script("arguments[0].click();", nxt)

However I want to change the else with elif and then else so it will look in this order:

    if len(buttons) > 0:
        for idx in range(len(buttons)):
            buttons[idx].send_keys('\n')
            res += 1
        time.sleep(1)
        driver.refresh()
    elif:
        nxt = driver.find_element(By.CSS_SELECTOR, ".paging_bootstrap i.fa-angle-right.fa")
        driver.execute_script("arguments[0].click();", nxt)
    else:
        print("Message")

Any ideas how to do it?

MetraDZ · Accepted Answer · 2020-09-08 11:44:54Z

1

buttons = driver.find_elements(By.XPATH, "...xpath")
    if len(buttons) > 0:
        for idx in range(len(buttons)):
            buttons[idx].send_keys('\n')
            res += 1
        time.sleep(1)
        driver.refresh()
    else:
        try:
            nxt = driver.find_element(By.CSS_SELECTOR, ".paging_bootstrap i.fa-angle-right.fa")
            driver.execute_script("arguments[0].click();", nxt)
        except Exception as e:
            print(e.message)

What do you think about this one?

P.S. Its pretty difficult to figure out, what do you want to achieve with this code, add some more explanation.

answered Sep 8, 2020 at 11:44

MetraDZ

396 bronze badges

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Comments

Jayanth Srivastav · Accepted Answer · 2020-09-08 11:48:23Z

1

You are almost correct. You just need to add the condition for elif block like len(buttons) == 0. For example your code can be written as:

if len(buttons) > 0:
        for idx in range(len(buttons)):
            buttons[idx].send_keys('\n')
            res += 1
        time.sleep(1)
        driver.refresh()
elif len(buttons) == 0:
        nxt = driver.find_element(By.CSS_SELECTOR, ".paging_bootstrap i.fa-angle-ight.fa")
        driver.execute_script("arguments[0].click();", nxt)
else:
        print("Message")

answered Sep 8, 2020 at 11:48

Jayanth Srivastav

816 bronze badges

2 Comments

MetraDZ Over a year ago

You think, its possible to get amount of buttons < 0??

Jayanth Srivastav Over a year ago

I'm assuming the bbfl is looking for the if..elif..else format and just gave an example. This is definetly not a valid scenario.

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