use array in bash for change name of created folder in each loop

Question

I am trying to do a script in bash and the idea is that I have an array with text and I use to creat a folder, for example:

#!/bin/bash
dir=(dir1 dir2 dir3)
for i in 0 1 2; do
    d=run_${#dir[i]}
    echo "Prepare case ${d}..."
done

My problem is that when I do this, it prints:

Prepare case run_4...
Prepare case run_4...
Prepare case run_4...

and the number 4 corresponds to the lenght of each array element, (if I change dir1 to direc1 for example, I get in the first line of the output "Prepare case run_6...")

What i was looking:

Prepare case run_dir1...
Prepare case run_dir2...
Prepare case run_dir3...

What i am missing?

why not just use your $i directly, or at least d=run_${i}. Good luck. — shellter
– shellter, Commented Sep 23, 2020 at 14:09

Ivan · Accepted Answer · 2020-09-23 13:51:56Z

1

Remove # from this commnd d=run_${#dir[i]}

And you can loop over array values like this:

for i in "${dir[@]}"; do
    echo "Prepare case run_$i..."
done

answered Sep 23, 2020 at 13:51

Ivan

7,5311 gold badge22 silver badges27 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

use array in bash for change name of created folder in each loop

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related