Python string formatting when iterating through lists

Question

I have a simple program that takes a sentence and calculates the number of lowercase, uppercase, digits and punctuation characters. I need to output into a format like this:

# Upper   # Lower   # Digits  # Punct.
--------  --------  --------  --------
   2         36        4         5

However, in my code, I have combined the headers, bars and the counts into a separate list. Here is my code:

#Prompting user to enter a sentence
input_string = input("Please enter a sentence: ")

#Initializing variables
lowercase_count = 0
uppercase_count = 0
punctuation_count = 0
digits_count = 0

#Iterating through the string to get the counts
for str in input_string:
    if str.isupper():
        uppercase_count +=1
    elif str.islower():
        lowercase_count +=1
    elif str in (".", "?", '!', ",", ";", ":", "-", "\'" ,"\""):
        punctuation_count +=1
    elif str.isnumeric():
        digits_count +=1

header_list = ["# Upper", "# Lower", "# Digits", "# Punct."]
bars_list = ['----------']*4
counts_list = [uppercase_count
               , lowercase_count
               , digits_count
               , punctuation_count]

comb_list = [header_list, bars_list, counts_list]

for list in comb_list:
    print("{:15}{:15}{:15}{:15}".format(list[0], list[1], list[2], list[3]))

Which gives me an output like this:

# Upper        # Lower        # Digits       # Punct.       
----------     ----------     ----------     ----------     
              1             16              0              1

If I were to print out the header, list and counts separately, I can control the align parameter

#Printing Header
print("{:15}{:15}{:15}{:15}"
      .format(header_list[0], header_list[1], header_list[2], header_list[3]))

#Printing bars
for header in header_list:
    print("{:15}".format("----------"), end="")

#Printing values
print("\n{:5}{:15}{:15}{:15}"
      .format(uppercase_count
              , lowercase_count
              , digits_count
              , punctuation_count))

which gives me the expected output:

# Upper        # Lower        # Digits       # Punct.       
----------     ----------     ----------     ----------     
    1             16              0              1

How do I control the align parameter when iterating through list of lists? What's the best way to print the output?

Joe Ferndz · Accepted Answer · 2020-09-28 04:17:09Z

2

New Response:

I looked at your code and the way your header is formatted, there is some alignment to be done. So try this and it will center itself. For every column, I am subtracting 5 and adding it to the next column. The reason: you have a space of 5 chars between each column. So I have to adjust for that.

print("\n{:^10}{:^20}{:^10}{:^20}"

The alternate to do this is:

print("\n{:^10}     {:^10}     {:^10}     {:^10}"

The output for this are as follows:

# Upper        # Lower        # Digits       # Punct.       
----------     ----------     ----------     ----------     
    1              16             0              1          

    32             16             7              12

Earlier response:

Can you try to give the following to center it:

print("\n{:^15}{:^15}{:^15}{:^15}"

To format the data, use one of these options. By default, strings are left justified and numbers are right justified.

< is for left justified
> is for right justified
^ is for center justified

You can learn more about formatting here

edited Sep 28, 2020 at 4:17

answered Sep 28, 2020 at 1:40

Joe Ferndz

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4 Comments

CrazyCoder Over a year ago

I tried this formatting but didn't give me the expected results

Joe Ferndz Over a year ago

I made some updates based on your code. See the results now.

CrazyCoder Over a year ago

why are we adding a space inside the print?

Joe Ferndz Over a year ago

Your text is setup that way so we need to either provide space or use 10,20,10,20 option

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