react - .include return unexpected result

Question

I have an string array with below value

const lists = ["EH-AA","EH-BB","EH-CC"]

I tried to use below code and I expect this statement return true.

lists.includes('EH-')

But it returns false actually.
How should I modify the condition statement so that it will return true

what is list? Is it a string that looks like an array, or is it an array containing 3 strings? Please edit your question to format that line of code because it changes the whole meaning of this question. — yqlim
– yqlim, Commented Nov 8, 2020 at 1:54

Jayce444 · Accepted Answer · 2020-11-08 01:55:13Z

1

That's not how includes works, it checks the array for that exact value. You need to loop over each item in the list and check if that item has that substring. You can do that with .some:

lists.some(item => item.includes('EH-'))

answered Nov 8, 2020 at 1:55

Jayce444

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kind user · Accepted Answer · 2020-11-08 01:59:35Z

1

You could also join the array and then check if it includes the specified string.

const lists = ['EH-AA', 'EH-BB', 'EH-CC'];

const checkForStr = (arr, str) =>
   arr.join(',').includes(str);

console.log(checkForStr(lists, 'EH-'));
console.log(checkForStr(lists, 'random'));

answered Nov 8, 2020 at 1:59

kind user

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