Python split string into multiple parts

Question

I have this string:

"[22.190894440000001, -100.99684750999999] 6 2011-08-28 19:48:11 @Karymitaville you can dance you can give having the time of my life(8) ABBA :D"

Where

the two numbers inside the [] are lat and lang
6 is value
2011-08-28 is the date
19:48:11 is the time
rest is the text

I want to separate this string into a list of length 5, in the following format: [lat, lang, value, date, time, text]

what is the most efficient way to do so?

You could use regex to parse the string. docs.python.org/3/library/re.html — christoandrew
– christoandrew, Commented Nov 11, 2020 at 9:23
Can you share what you’ve tried / researched on the subject yourself, before posting to SO? Please update the question accordingly. — s3dev
– s3dev, Commented Nov 11, 2020 at 9:25

taras · Accepted Answer · 2020-11-11 09:28:20Z

2

You can make use of str.split with maxsplit argument controlling the number of splits. Then you can strip the comma and brackets from lat and lang:

>>> text = "[22.190894440000001, -100.99684750999999] 6 2011-08-28 19:48:11 @Karymitaville you can dance you can give having the time of my life(8) ABBA :D"
>>> lat, lang, value, date, time, text = text.split(maxsplit=5)
>>> lat, lang, value, date, time, text
('[22.190894440000001,', '-100.99684750999999]', '6', '2011-08-28', '19:48:11', '@Karymitaville you can dance you can give having the time of my life(8) ABBA :D')
>>> lat = lat.strip('[').rstrip(',')
>>> lang = lang.rstrip(']')
>>> lat, lang, value, date, time, text
('22.190894440000001', '-100.99684750999999', '6', '2011-08-28', '19:48:11', '@Karymitaville you can dance you can give having the time of my life(8) ABBA :D')

answered Nov 11, 2020 at 9:28

taras

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Comments

ErdoganOnal · Accepted Answer · 2020-11-11 09:38:59Z

1

Here is a solution using regex.

import re

text = "[22.190894440000001, -100.99684750999999] 6 2011-08-28 19:48:11 @Karymitaville you can dance you can give having the time of my life(8) ABBA :D"
regex = re.compile(r"\[(?P<lat>\d+.\d+), +(?P<lang>-?\d+.\d+)\] +(?P<value>.+?) *(?P<date>.+?) +(?P<time>.+?) +(?P<text>.*)")

result = regex.match(text)

print(result.group("lat"))
print(result.group("lang"))
print(result.group("value"))
print(result.group("date"))
print(result.group("time"))
print(result.group("text"))

The result:

22.190894440000001
-100.99684750999999
6
2011-08-28
19:48:11
@Karymitaville you can dance you can give having the time of my life(8) ABBA :D

answered Nov 11, 2020 at 9:38

ErdoganOnal

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