Search Array In Python, Return Position

Question

This Is Quite Simple but I cant get the hang of it. I'm writing a short program where you enter the name, it will compare to each item in the array, then if it is found print what number it is in the array. if it isnt found, then enter a new name

Names = ['alice', 'bob', 'carol', 'david']
name = input("Enter Name ").lower()
c = 0
while name != Names[c]:
    c = c + 1
    if c == (len(Names)):
        name = input("Name Not Found \n \nEnter Name ").lower()
        c = 0
if name == Names[c]:
    print ("name found, in position ", c)

It Always Comes Up With Name Not Found

Pro Grammar · Accepted Answer · 2020-11-12 19:31:50Z

2

name.lower without the () at the end will return the whole lower function and it will mess with the variable

So just replace that with name.lower() and it should work

answered Nov 12, 2020 at 19:31

Pro Grammar

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marsnebulasoup · Accepted Answer · 2020-11-12 19:51:17Z

1

Alternatively, you could use Name.index(name) and create a recursive function to search for names, like so:

Names = ['alice', 'bob', 'carol', 'david']

def findName():
  name = input("Enter Name: ").lower()
  if name in Names:
    print(f'Name at position {Names.index(name)}')
  else: 
    print('Name not found; try again')
    findName()

findName()

Or the same code but in a loop:

while True:
  name = input("Enter Name: ").lower()
  if name in Names:
    print(f'Name at position {Names.index(name)}')
    break
  else: 
    print('Name not found; try again')

answered Nov 12, 2020 at 19:51

marsnebulasoup

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DiscountGoggins · Accepted Answer · 2020-11-12 19:40:36Z

1

Use name = input("Enter Name ").lower() instead of name = input("Enter Name ").lower. name = input("Enter Name ").lower would assign name to the function lower, while name = input("Enter Name ").lower() runs the function lower and assigns name its return value

answered Nov 12, 2020 at 19:40

DiscountGoggins

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