Getting a new array from another array based on matching value

Question

I have an array of thousands objects and need to check if a specific value is included in one of the values.

My array:

const images = [
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["pink", "yellow", "red"],
  },
  {
    "name" : "old car",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark purple", "sand", "light green"],
  },
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark blue", "violet"],
  },
...
]

and I'm trying to get a new array that contains only those objects which include a specific colour. Also the value must be a perfect match: i.e. if I pass "blue" it should return false if it checks against "dark blue"

I'm trying to do the following but running into errors

const checkColourtHandler = async (selectedColour) => {
   const imageList = images.filter(function (item, i) {
        if (item.colours.includes(selectedColour)) {
          return true;
        } else return false;
   });
   console.log(imageList);
}

Ideally I'm looking for the best performant method as well.

Brian Lee · Accepted Answer · 2020-11-23 13:00:36Z

1

Use the filter and includes methods to check for matching elements:

const images = [
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["pink", "yellow", "red"],
  },
  {
    "name" : "old car",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark purple", "sand", "light green"],
  },
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark blue", "violet"],
  }
];

const filtered = (col) => images.filter(i => i.colours.includes(col));

const output = filtered('dark blue');

console.log(output);
console.log(filtered('blue'));

edited Nov 23, 2020 at 13:00

answered Nov 23, 2020 at 12:18

Brian Lee

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8 Comments

Butri Over a year ago

Thanks @DigitalDrifter it looks like it is working however it returns a function. In reality I'm trying to get the array as final result so I can save it and use it elsewhere.

Brian Lee Over a year ago

Where is it returning a function? I'm just defining filtered as a function and calling it with desired color string: filtered('dark blue');. That can change to suit your implementation needs, of course.

Butri Over a year ago

Well I need to get and save the array result of that function somewhere. So the way I see it is that there are 2 steps: run the function and save the result in other variable so I can access it and use it elsewhere.

Brian Lee Over a year ago

I updated the answer. You'll see const output = filtered('dark blue'); now so you can reference the output array later in your code.

Butri Over a year ago

That is not working for me for some reason. I have const output = filtered('dark blue'); within another function and filtered() separate and I'm getting Unhandled promise rejection: TypeError: undefined is not an object (evaluating 'i.colours.includes'

|

Ran Marciano · Accepted Answer · 2020-11-23 12:18:21Z

0

This should do it

const images = [
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["pink", "yellow", "red"],
  },
  {
    "name" : "old car",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark purple", "sand", "light green"],
  },
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark blue", "violet"],
  }
];

const checkColourtHandler = (selectedColour) => images.filter(item => item.colours.includes(selectedColour));

console.log(checkColourtHandler("sand"));
console.log(checkColourtHandler("violet"));

answered Nov 23, 2020 at 12:18

Ran Marciano

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Comments

Brian Lee · Accepted Answer · 2020-11-23 13:37:58Z

0

@DigitalDrifter

Updating my code here

const images = [
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["pink", "yellow", "red"],
  },
  {
    "name" : "old car",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark purple", "sand", "light green"],
  },
  {
    "name" : "sky",
    "width" : "90",
    "height" : "150",
    "colours" : ["dark blue", "violet"],
  }
];

const filtered = (col) => images.filter(i => i.colours.includes(col));

const checkColourtHandler = (selectedColour) => {
    const result = filtered(selectedColour); 
    console.log("result: ",result);
  }

checkColourtHandler('pink');

edited Nov 23, 2020 at 13:37

Brian Lee

18.3k3 gold badges45 silver badges55 bronze badges

answered Nov 23, 2020 at 13:33

Butri

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1 Comment

Butri Over a year ago

Find the problem, another error in my code was causing a conflict. Many thanks for your help!

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