selenium - python - find element by inner HTML

Question

I want to fetch the following web element using selenium and python

<td class="letterbreak first">default</td>

And I want to find it based on the inner HTML text default. I can't use the class because there are other elements using the same class. I have tried:

driver.find_element(By.XPATH,"//*[contains(@innerHTML,'default')]")

But I get a NoSuchElementException.

Is it possible to find based on innerHTML? If so, how can I do it?

@arundeepchohan that did not work but driver.find_element(By.XPATH,"//*[text()='default']") did. Thanks. — iamthebull
– iamthebull, Commented Dec 15, 2020 at 22:10

KunduK · Accepted Answer · 2020-12-15 21:51:59Z

2

Use either of the xapth.

driver.find_element(By.XPATH,"//*[contains(text(),'default')]")

OR

driver.find_element(By.XPATH,"//*[text()='default']")

To avoid synchronization issue induce WebDriverWait() and wait for visibility_of_element_located() and following xpath

WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//*[contains(text(),'default')]")))

You need to import below libraries.

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

answered Dec 15, 2020 at 21:51

KunduK

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1 Comment

iamthebull Over a year ago

The second format worked but the first did not. Does the first do a partial match and the second an exact match?

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