Filter JavaScript Array of Objects based on Objects Key

Question

I have an array of objects I generated from a JSON response.

The content of said array is structured like this:

const array = [
{title: "user generated title", message: "random user generated text", status: "Active/Inactive"},
 {200 + more objects with the exact same key/values as the first},
...,
...
]

I want to make a new array with the exact same objects minus specific key/value pairs.

I.e., to make the exact same array with out say all message: "user message" key/value pairs. (There are multiple key/value pairs I want to remove from the objects in the array though.)

so it would be like

const array = [
{title: "user generated title", status: "Active/Inactive"},
{200 + objects just like the first without the message: "message text"},
...,
...
]

Array of objects is not diffrent from another array, iterate it with for or foreach loop and then you can iterate through the object key and value using Object.entries() (developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…).. and of course add to new array only the objects with the keys and values that you need. — ValeriF21
– ValeriF21, Commented Dec 24, 2020 at 22:57
Does this answer your question? Remove property for all objects in array — pilchard
– pilchard, Commented Dec 24, 2020 at 23:18

Mureinik · Accepted Answer · 2020-12-24 22:50:55Z

3

You could go over them and delete those keys:

array.forEach(o => delete o.message);

answered Dec 24, 2020 at 22:50

Mureinik

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Comments

Eduardo Poço · Accepted Answer · 2020-12-24 22:53:58Z

1

var newArray = [];
for (var i = 0; i < array.length; i++) {
    var obj = array[i];
    
    if (!("message" in obj)) { //put the conditions to keep the object here
        newArray.push(obj); //copy reference to new array
    }
}

answered Dec 24, 2020 at 22:53

Eduardo Poço

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