Push Values from different array to Different Keys

Question

i have 2 array like this :

let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}]

and

let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}]

how can i pushing values from payrollbalance to payrollname ?

i mean push like this, values from payrollbalance.a4 which mean 300000 push to payrollname.code == a4

and i hope final results can similar like :

let result = `[{"code": "a1", "name": "Loan A", "values": 0}, {"code": "a2", "name": "Loan B", , "values": 100000}, {"code": "a3", "name": "Loan C", "values": 500000}, {"code": "a4", "name": "Loan D", "values": 300000}, {"code": "a5", "name": "Loan E",  "values": 45900}]`

any help will be appricated, im already messing up whole days.

thanks in advance

Is there a reason payrollbalance is an array? Can it have more than one object? — Nick Parsons
– Nick Parsons, Commented Dec 28, 2020 at 8:15
Ok, can you also add your attempts to far (even if they don't work?) then you can see where you went wrong — Nick Parsons
– Nick Parsons, Commented Dec 28, 2020 at 8:17
@NickParsons im trying to manipulate render at front end (because i cant change their backend) like this.state.payrollbalance+'.a4' but return always be [object Object].a4 — Tumbalakun
– Tumbalakun, Commented Dec 28, 2020 at 8:21
@Tumbalakun Better to share attempt for such question and find out what went wrong instead of expecting someone to solve it for you. Till now you have been messing up whole day, If someone solve it for you then you will be messing up for whole life. — sourav satyam
– sourav satyam, Commented Dec 28, 2020 at 8:21

topdev87 · Accepted Answer · 2020-12-28 08:27:08Z

1

Use Array.map() and add values key with the value of payrollbalance[0] with indicating the json key by [] for dynamic.

let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}]

let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}]

let result = payrollname.map(item => ({
  ...item,
  values: payrollbalance[0][item.code]
}));

console.log(result);

edited Dec 28, 2020 at 8:27

answered Dec 28, 2020 at 8:18

topdev87

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Pascal Tovohery · Accepted Answer · 2020-12-28 08:31:07Z

0

Make an array seach, find the index and change it after

let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}]
let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}]
var result = [];
let pblance = payrollbalance[0]
for(let p in pblance)
{
  let index = payrollname.findIndex(el => el.code==p)
  let pname = payrollname[index]
  pname.values = pblance[p];
  result.push(pname)
}
console.log(result);

answered Dec 28, 2020 at 8:31

Pascal Tovohery

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4 Comments

topdev87 Over a year ago

since you did findindex inside for() loop, the o notation will be o(n*n), that the performance is not good.

Pascal Tovohery Over a year ago

@WilliamWang i should use .indexOf instead of findIndex

topdev87 Over a year ago

no, it's same. indexOf also iterate the array.

topdev87 Over a year ago

you can just call the object dynamic key using []. refer to above my answer.

Mahdi Teymouri · Accepted Answer · 2020-12-28 08:35:51Z

0

this code will work !

let payrollname = [{"code": "a1", "name": "Loan A"}, {"code": "a2", "name": "Loan B"}, {"code": "a3", "name": "Loan C"}, {"code": "a4", "name": "Loan D"}, {"code": "a5", "name": "Loan E"}]
let payrollbalance = [{"a1": 0, "a2": 100000, "a3": 500000, "a4": 300000, "a5": 45900}]
let result = []
let i = 0
payrollname.forEach(element => {
    let value = payrollbalance[0][element.code]
    element.values = value;
    result[i] = element
    i=i+1
});
console.log(result)

answered Dec 28, 2020 at 8:35

Mahdi Teymouri

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