API call via url in django

Question

I'm attempting to make an api call in django to a url.

#api call
url = "https://api.lemlist.com/api/team"
querystring = {"user":apikey}
response = requests.request("GET", url, params=querystring)

Lemlist shows that the following call can be made as follows, but its in a different language:

curl https://api.lemlist.com/api/team \
  --user ":YourApiKey"

With the python call noted above, I'm getting a 400 error.

Thanks!

drec4s · Accepted Answer · 2021-02-28 12:06:44Z

1

--user in curl means basic authentication, so you need to use the Basic Authentication provided by the requests module.

url = "https://api.lemlist.com/api/team"
response = requests.get(url, auth=('', 'YourApiKey'))

answered Feb 28, 2021 at 12:06

drec4s

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3 Comments

Thanks! this is a great help

It's very odd, but this didn't work. got a 401 error.

did you put the : just before your API key ?