How to extract data from an object in python

Question

I am getting an exception which am transferring to a variable. The output of the variable is given below:

schema.SchemaError("Key 'policy' error:\nOr({'name': And(<class 'str'>, <built-in function len>), 'age': And(<class 'int'>, <function <lambda> at 0x000001C964E92DC8>), Optional('gender'): And(<class 'str'>, Use(<method 'lower' of 'str' objects>), <function <lambda> at 0x000001C964E92E58>)}) did not validate {'name': 'Sue', 'age': 28, 'gnder': 'Squid'}\nWrong key 'gnder' in {'name': 'Sue', 'age': 28, 'gnder': 'Squid'}")

Please let me know how I can get the contents of this variable, I could try to convert this into a string but then it becomes very cumbersome to extract the contents. I specifically want the contents after 'did not validate' part.

EDIT - Not looking to resolve the error, error was expected. I transferred the contents of the exception to a variable, just need to figure out how to read the variable.

Please provide a reduced version of the code that resulted in that error, and if possible also a minimized version of the input data. — 0x6d64
– 0x6d64, Commented Apr 29, 2021 at 10:16
Hey, am not looking to resolve the error, error was expected. I transferred the contents of the exception to a variable, just need to figure out how to read the variable. — arunmenon
– arunmenon, Commented Apr 29, 2021 at 10:19
Nope the error is fine, am just unable to read the error, I want the contents of the error, currently its coming as a data type as shown above. I want to get which key was wrong from the error output. — arunmenon
– arunmenon, Commented Apr 29, 2021 at 10:33

Pear · Accepted Answer · 2021-04-30 07:49:52Z

2

Store it in variable
Convert to string
Search for did not validate in the converted string
the string lies in 127th position
search for { in the string as it is the starting after the error
takeout the thing after the position
convert it to any form you want
ALSO: print the variable a for confirmation
CODE :

a = schema.SchemaError("Key 'policy' error:\nOr({'name': And(<class 'str'>, <built-in function len>), 'age': And(<class 'int'>, <function <lambda> at 0x000001C964E92DC8>), Optional('gender'): And(<class 'str'>, Use(<method 'lower' of 'str' objects>), <function <lambda> at 0x000001C964E92E58>)}) did not validate {'name': 'Sue', 'age': 28, 'gnder': 'Squid'}\nWrong key 'gnder' in {'name': 'Sue', 'age': 28, 'gnder': 'Squid'}")
a = str(a)
b = 127 #every error starts from here
a = a[b:len(a)]
c = a.find("{")
a = a[c:len(a)]
print(a)

edited Apr 30, 2021 at 7:49

answered Apr 29, 2021 at 10:33

Pear

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3 Comments

arunmenon Over a year ago

Almost solved, getting this: "{'name': 'Sue', 'age': 28, 'gnder': 'Squid'}\nWrong key 'gnder' in {'name': 'Sue', 'age': 28, 'gnder': 'Squid'}" Any way I could convert this into a dictionary?

arunmenon Over a year ago

Cannot accept this as an answer as 'did not validate' string won't be there for every error, sometimes there is 'key not found', 'datatype wrong' etc.

Pear Over a year ago

@arunmenon Now the problem of other errors are solved ;)

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