Numpy concatenate void binary buffers

Question

I have a numpy array

a = [void(b'\x0A\x00\x01\x02'),
     void(b'\x0B\x02\x03\x04'),
     void(b'\x0C\x07\x03\x04')
    ]

I want something like b'\x0A\x00\x01\x02\x0B\x02\x03\x04\x0C\x07\x03\x04'

Right now I am doing it using loop

result = bytearray()
for b in a:
   result += bytearray(b)

Is there any numpy kind of way to do it, so that it becomes fast.

Kevin · Accepted Answer · 2021-05-01 20:01:13Z

1

If you are working with numpy arrays, the easiest would probably be to call the tobytes() method.

from numpy import void 

a = [void(b'\x0A\x00\x01\x02'),
     void(b'\x0B\x02\x03\x04'),
     void(b'\x0C\x07\x03\x04')
    ]

np.array(a).tobytes()

Output:

b'\n\x00\x01\x02\x0b\x02\x03\x04\x0c\x07\x03\x04'

answered May 1, 2021 at 20:01

Kevin

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