So I want the input of argparse to be a string instead of the command line. for example:
python3 some_script.py arg1 arg2 arg3
I want to give the argparse the string "arg1 arg2 arg3"
import argparse
command = "arg1 arg2 arg3"
parser = argparse.ArgumentParser()
# add args here
args = parser.parse_args()
# process the command here and extract values
You can use list directly in parse_args()
args = parser.parse_args(["arg1", "arg2", "arg3"])
or you can use your line
command = "arg1 arg2 arg3"
args = parser.parse_args(command.split(" "))
You can always put it in sys.argv and parser should use it
import sys
sys.argv = ["script", "arg1", "arg2", "arg3"]
it can be useful if you want to append() some option to values which you get from command line
sys.argv.append("--debug")
If you have more complex command with quoted strings like
'arg1 "Hello World" arg3'
then you can use standard module shlex to split it correctly into three arguments
import shlex
shlex.split('arg1 "Hello world" arg3')
['arg1', 'Hello World', 'arg3'].
Normal command.split(" ") would incorrectly give four arguments
['arg1', '"Hello', 'World"', 'arg3']
def _parse_args(args=sys.argv[1:]) to make it easier to test them, then I can just provide the test args when calling the function instead of having to modify sys.argv manually during testing.
None as default and then it uses sys.argv automatically - so you could even do def _parse_args(args=None)
parser.parse_args( ["script", "arg1", "arg2", "arg3"] )did exactly what I wanted. it was mantioned here all along docs.python.org/3.8/library/…