SQL to Sequelize with nested select

Question

Need to write the following SQL Query in Sequelize Node js

select a, b, c
from (
    select tbl.*, 
       count(*) over(partition by a) cnt,
       row_number() over (partition by a order by b) brn,
       row_number() over (partition by a order by c) crn
    from tbl
    where c in (4, 5)
) t
where cnt = 2 and brn = crn;

This is what I've come up with. I cannot figure out where to put the condition where cnt = 2 and brn = crn;

t.findAll({
    attributes: {
        include: [
            [sequelize.literal('count(*) over(partition by a)'),'cnt'],
            [sequelize.literal('row_number() over (partition by a order by b)'),'brn'],
            [sequelize.literal('row_number() over (partition by a order by c)'),'crn'],
        ]   
    },
    where: {
            c: {[Op.in]:[4,5]},
        }
    })

Marko · Accepted Answer · 2021-05-08 15:36:28Z

1

Sequelize doesn't seem to support selecting from subqueries (https://github.com/sequelize/sequelize/issues/5354)

You can use a raw query instead (https://sequelize.org/master/manual/raw-queries.html):

const { QueryTypes } = require('sequelize');
let result = await sequelize.query(`
    select a, b, c
    from (
        select tbl.*, 
           count(*) over(partition by a) cnt,
           row_number() over (partition by a order by b) brn,
           row_number() over (partition by a order by c) crn
        from tbl
        where c in (4, 5)
    ) t
    where cnt = 2 and brn = crn;
`, {type: QueryTypes.SELECT});

answered May 8, 2021 at 15:36

Marko

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