Python - run an async funtion after delay and do not block other code

Question

Here is my code:

async def outer():
    # if this while loop was not broken in 5 seconds, do something
    while True:
        # some code with breaks

Generally i need a non-blocking asynchronous timer.

Do you mean if outer is not completed in 5 seconds you need to do something? — Ceres
– Ceres, Commented May 10, 2021 at 9:01

Ceres · Accepted Answer · 2021-05-10 09:57:16Z

1

def outer():
    async def loop():
         #while loop here
  

    task = asyncio.create_task(loop())
    done, pending = await asyncio.wait([task], return_when=asyncio.FIRST_COMPLETED, timeout=5)
    if task in done:
        # loop has completed
    else:
       # loop is incomplete

References:

asyncio.wait

answered May 10, 2021 at 9:57

Ceres

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