decode json in json with python

Question

When I try to load following json in python:

"foo": {
            "foo_id": "1",
            "foo_name": "i",
            "foo_client_id": "2",
            "foo_client": "b",
        }

I got following error:

json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)

How do I parse this as a legal json?

1) Wrap foo in another object ({}). 2) Remove trailing comma after b. — 0stone0
– 0stone0, Commented May 11, 2021 at 9:48
Does this answer your question? How to decode an invalid json string in python — 0stone0
– 0stone0, Commented May 11, 2021 at 9:50
What you have is not in valid JSON format — which doesn't allow that comma at the end of the last item (unlike Python). — martineau
– martineau, Commented May 11, 2021 at 10:06

bereal · Accepted Answer · 2021-05-11 09:51:22Z

0

This is not valid JSON due to the missing enclosing brackets and the trailing comma. However, it's valid YAML:

import yaml

data = '''
"foo": {
        "foo_id": "1",
        "foo_name": "i",
        "foo_client_id": "2",
        "foo_client": "b",
    }
'''
yaml.safe_load(data)  # returns a dict

answered May 11, 2021 at 9:51

bereal

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