Python Selenium. Element is not interactable

Question

I am trying to fill the form on (https://all-access.wax.io). When I am using Javascript

document.getElementsByName("userName")[0].value = "Hello", then I am able to write text to a form. However, when I am using same concept in selenuim

driver.find_element_by_name("userName").send_keys("Hello"), then I am getting:

selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable

When I am executing: self.driver.find_element_by_name("userName")[1].send_keys("Hello") this leads to:

TypeError: 'WebElement' object is not subscriptable

I have also tried to wait until content is loaded, as well as use XPath and other selectors. I guess I am doing a simple mistake, but I can`t resolve it for several hours already.

Code to reproduce a problem:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys

browser = webdriver.Chrome()
browser.get('https://all-access.wax.io')
browser.find_element_by_name("userName")[1].send_keys("hello")
print()

Arundeep Chohan · Accepted Answer · 2021-05-16 23:06:53Z

2

browser.find_element_by_xpath("(//input[@name='userName'])[2]").send_keys("hello")

You want to send_keys to the second input tag and not the first.

answered May 16, 2021 at 23:06

Arundeep Chohan

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Comments

PDHide · Accepted Answer · 2021-05-16 20:12:58Z

1

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys

browser = webdriver.Chrome()
browser.get('https://all-access.wax.io')
browser.find_element_by_name("userName").send_keys("hello")
print()

you are using find_element which returns a webelement and not array , use find_elements or remove the index

answered May 16, 2021 at 20:12

PDHide

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Comments

vitaliis · Accepted Answer · 2021-05-16 21:42:08Z

The approach with only name attribute did not work for me because when you are trying to access with [1] there are still two elements, so the locator is not unique. So, I used the parent pannels visible-desktop-only-flex class and also added explicit wait.

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait

browser = webdriver.Chrome(executable_path='/snap/bin/chromium.chromedriver')


browser.get('https://all-access.wax.io')
wait = WebDriverWait(browser, 15)
wait.until(EC.element_to_be_clickable((By.XPATH, "//div[@class='pannels visible-desktop-only-flex']//input[@name='userName']")))
browser.find_element_by_xpath("//div[@class='pannels visible-desktop-only-flex']//input[@name='userName']").send_keys("hello")

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