I am doing some calculations and I was wondering how you can invert a byte in python.
For example:
0b11111111 should be flipped to 0b00000000.
I have tried turning into a string and flipping it then but I cant somehow turn it back into a Integer.
Also, I want to add that the ~ does not work, as it simply just makes the same number but negative
bin(0b11010111 ^ 0b11111111) // bit subtraction
# Result
# bin(0b11010111 ^ 0b11111111)
#'0b101000'
# for each bit subtraction with 1 occur
To explain why ~ "dit not work": you want to invert all bits in a byte (8-bits), but the 0b.... value is not a byte, but an int which has more bits than just 8.
~var inverts all bits in an integer. You can clear all bits except the lowest 8 with a mask to get the result you expect:
MASK8 = 0b11111111 # or 255 decimal
v = 0b11101110
inv = ~v & MASK8 # 0b10001
def flippingBits(n):
binary_list=list(bin(n))[2::]
binary_32=''
binary_result=''
for item in binary_list:
if item=='1':
binary_32+='0'
else:
binary_32+='1'
if 32-len(binary_list)>0:
for i in range(32-len(binary_list)):
binary_result+='1'
binary_result+=binary_32
else:
binary_result=binary_32
result=int(binary_result, 2)
return result
This is a solution a made for a flipping bits in hacker rank: The function receive an unsigned int, turn this number into a binary representation and flip all the bits in a 32 bits representation, then return the unsigned int number corresponding to the remaining binary number. First I change into the binary representation using the bin() function, then i tansform that into a string with a for loop but changing every bit for the opposite(flipping), last I concatenate the string with the difference between the string length and the 32 spaces I need (32 bits), adding 1s to the rest of the string. Last I change into an integer using int(number, base) function. I hope it helps you.
^operator.^ 0b111111110b10101 ^ 0b11111111 == 0b11101010a = 0b11111111^0b00101010 print(bin(a))This gives me The opposite