define javascript variable from php variable within php code

Question

I am trying to define javascript variable from php variable in the running php code.

Here is my code:

echo "<script>"; 
echo "var s1 = '<?php echo isset($s1) ? $s1 : ''  ?>';";
echo "getAirdrop();";
echo "</script>";

But this code not defining the javascript variable.

You're already in a PHP block. Adding <?php is completely unnecessary. — aynber
– aynber, Commented Jul 23, 2021 at 12:25

Gerard de Visser · Accepted Answer · 2021-07-23 12:35:33Z

1

You don't need php tags again.

Try it like this:

echo "<script>";
echo "var s1 = '";
echo isset($s1) ? $s1 : '';
echo "';";
echo "getAirdrop();";
echo "</script>";

answered Jul 23, 2021 at 12:28

Gerard de Visser

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Comments

Laurent Callens · Accepted Answer · 2021-07-23 15:06:26Z

1

You can do it in one line, just concatenate all yours echo :

echo "<script> let s1 = ".isset($s1) ? $s1 : ''." getAirdrop(); </script>"

answered Jul 23, 2021 at 15:06

Laurent Callens

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