Place every 2 strings into an array in an array in angular

Question

I'm working with an angular project. I have a string like below and i sorted out all the special characters using regular expressions. Now, I want the first 2 strings to be in suare brackets and the second two in another square bracket like coordinates, and the output should be like below. Please help me achieve the functionality.

test: any = "((-1.23568 75.87956), (-1.75682 22.87694))"

My ts code be like:


  hello()
  {
      this.new = ( this.test.replace(/[^\d. -]/g, ''));
      this.newarr = this.new.split(" ");    
      const result =  this.newarr.filter(e =>  e);
  }

and my final output in result array is like:

["-1.23568", "75.87956", "-1.75682", "22.87694"]

Desired output

[ ["-1.23568", "75.87956"], ["-1.75682", "22.87694"] ]

Terry Lennox · Accepted Answer · 2021-11-05 16:18:12Z

1

Another approach would be to use String.match() to get each group of coordinates, then Array.map() and String.split() to divide into pairs.

let test = "((-1.23568 75.87956), (-1.75682 22.87694))";
const result = test.match(/[\d.-]+\s[\d.-]+/g).map(s => s.split(/\s/));
console.log('Result:', result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Nov 5, 2021 at 16:18

answered Nov 5, 2021 at 15:47

Terry Lennox

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2 Comments

chlara Over a year ago

Thanks for the response. As of now, we are putting every 2 strings into an array. But, what is the solution if we want to place every 2 strings in between the square brackets and pass the same into a variable ? Ex: test = [[string1, string2 ],[string1, string2], and so on ]. If I want to read index 0 - the value should be test = [string1, string2] and so on I can read any index and it should cone with square brackets.

Terry Lennox Over a year ago

I expect one could modify the solution in that case, if you add that variant to the question it would be helpful, thanks!

Eugene Porodko · Accepted Answer · 2021-11-05 15:01:54Z

1

For example you can use Array.prototype.splice(). This function can give you such 'portions' for your new array:

pairs.push(initialArr.splice(0, 2))

Juts loop through your initial array initialArr.length/2 times.

Working demo

EDIT: Or maybe you can update your replacing logic for getting not just number after number but pairs (for example '-1.23568 75.87956,-1.75682 22.87694') and then just split it twice.

split(',') --> ['-1.23568 75.87956', '-1.75682 22.87694']

and then loop and

split(' ')

edited Nov 5, 2021 at 15:01

answered Nov 5, 2021 at 14:54

Eugene Porodko

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2 Comments

chlara Over a year ago

Thanks for the response. I didn't get your edit answer, can you please elaborate it.

Eugene Porodko Over a year ago

@chlara check pls here

munleashed · Accepted Answer · 2021-11-05 15:34:11Z

1

You can avoid some complex regex logic and just, once you have:

const [a1, a2, b1, b2] = ["-1.23568", "75.87956", "-1.75682", "22.87694"]

const result = [[a1, a2], [b1, b2]]

Or if there are more than two pairs:

const array = ["-1.23568", "75.87956", "-1.75682", "22.87694", "-1.33343", "3.34432"]

const result = [];
for(let i = 0; i < array.length; i+=2) {
  result.push(array.slice(i, i+2))
}

answered Nov 5, 2021 at 15:34

munleashed

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2 Comments

chlara Over a year ago

Thank you for the response. It worked.

chlara Over a year ago

All the three answers worked for me.

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