Async function is not working asynchronously

Question

I have a question.

I wrote a simple code that mimics http request:

from asyncio import sleep, run


async def get():
    print("Started get()")
    await sleep(3)
    print("Finished get()")


async def async_main():
    await get()
    await get()
    await get()


if __name__ == "__main__":
    run(async_main())

I expected that the result should be like:

Started get()
Started get()
Started get()
(No output, just wait 3 seconds)
Finished get()
Finished get()
Finished get()

But the result was:

Started get()
(No output, just wait 3 seconds)
Finished get()
Started get()
(No output, just wait 3 seconds)
Finished get()
Started get()
(No output, just wait 3 seconds)
Finished get()

Why is this happening?

Because you're awaiting them 1 by 1. You're looking for asyncio.gather. It'll be something like await asyncio.gather(get(), get(), get()) — Konstantin K.
– Konstantin K., Commented Jan 8, 2022 at 3:35

Bharel · Accepted Answer · 2022-01-08 13:27:57Z

2

You need to schedule the coroutines, either explicitly using asyncio.create_task() or implicitly using asyncio.gather():

from asyncio import sleep, run


async def get():
    print("Started get()")
    await sleep(3)
    print("Finished get()")


async def async_main():
    tasks = [asyncio.create_task(get()), 
             asyncio.create_task(get()),
             asyncio.create_task(get())]  # Explicit
    await asyncio.gather(*tasks)

async def async_main(): # Option 2
    await asyncio.gather(get(), get(), get())  # Implicit

if __name__ == "__main__":
    run(async_main())

answered Jan 8, 2022 at 13:27

Bharel

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Comments

Mahamudul Hasan · Accepted Answer · 2022-01-08 14:22:02Z

2

just run the task asynchronously like below

async def async_main():
    await asyncio.gather(get(), get(), get())

if __name__ == "__main__":
    # run(async_main()) or
    asyncio.run(async_main())

edited Jan 8, 2022 at 14:22

answered Jan 8, 2022 at 14:13

Mahamudul Hasan

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