How to read query param value if special character (&) part of query param value

Question

Url: https://myproject.dev.com/methodology/Culture?contentName=abc & def&path=Test&type=folder

Need to fetch only query params from above URL but problem is '&' in contentName=abc & def so while fetching the contentName getting the value in two parts like abc, def.

Please suggest the approach to get contentName is abc & def instead of abc,def.

Hitesh A. Bosamiya · Accepted Answer · 2022-01-20 06:33:13Z

1

If the & character is part of the name or value in the query string then it has to be percent encoded. In the given example: contentName=abc%26def&path=Test&type=folder.

answered Jan 20, 2022 at 6:33

Hitesh A. Bosamiya

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2 Comments

Yellappa Over a year ago

Thanks for answer.If contentName=abc & def (included spaces)then encode abc%20%26%20def so this case it is not working as excepted

Hitesh A. Bosamiya Over a year ago

As per the specification the space should get encoded as '+'. As @Trisav pointed out you can use URLEncoder (wrongly named :-)) class.

TriS · Accepted Answer · 2022-01-27 07:09:40Z

If we pass any type of special character we have to encode those values. Java provides a URLEncoder class for encoding any query string or form parameter into URL encoded format. When encoding URI, one of the common pitfalls is encoding the complete URI. Typically, we need to encode only the query portion of the URI.

public static void main(String[] args) {
    Map<String, String> requestParameters = new LinkedHashMap<>();
    requestParameters.put("contentName", "abc & def");
    requestParameters.put("path", "Test");
    requestParameters.put("type", "folder");

    String encodedURL = requestParameters.keySet().stream()
            .map(key -> key + "=" + encodeValue(requestParameters.get(key)))
            .collect(Collectors.joining("&", "https://myproject.dev.com/methodology/Culture?", ""));
    System.out.println(encodedURL);
}

private static String encodeValue(String value) {
    String url = "";
    try {
        url = URLEncoder.encode(value, StandardCharsets.UTF_8.toString());
    } catch (Exception ex) {
        System.out.println(ex);
    }
    return url;
}

Output:

https://myproject.dev.com/methodology/Culture?contentName=abc+%26+def&path=Test&type=folder

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