JavaScript - Need help with string manipulation

Question

say you have:

var foo = "donut [$25]"

What would you need to do in order to delete everything between and including the [ ].

so you get: foo = "donut" after the code is run.

So far I have tried most of the solutions below, but they all either do nothing or crash. Maybe it's something with my code, please see below:

 $('select').change(function () { OnSuccess(mydata); });


    function OnSuccess(data) {

        var total = 0;

        $('select').each(function () {


            var sov = parseInt($(this).find('option:selected').attr('value')) || 0; //Selected option value

            var sop; //Selected Option Price


            for (i = 0; i <= data.length; i++) {


                if (data[i].partid == sov) {

                    sop = data[i].price;
                    total += sop;
                    $('#totalprice').html(total);
                    break;
                }


            };








            //debugger;
            $(this).find('option').each(function () {

                // $(this).append('<span></span>');

                var uov = parseInt($(this).attr('value')) || 0; //Unselected option value

                var uop; //Unselected Option Price


                for (d = 0; d <= data.length; d++) {


                    if (data[d].partid == uov) {

                        uop = data[d].price;
                        break;
                    }

                }
                //debugger;
                var newtext = uop - sop;
                //{ newtext = "" };
                //if (newtext = 0) { newtext.toString; newtext = ""; };


                //debugger;
                var xtext = $(this).text().toString();

                //if (xtext.match(/\[.*\]/) != null) {
                    xtext.replace(/\s*\[[\s\S]*?\]\s*/g, '').trim();

                //}

                //                var temp = xtext.split('[')[0];
                //                var temp2 = xtext.split(']')[1];

                //                resultx = temp + temp2;

                if (newtext != 0) {


                    //xtext.replace(/[.*?]/, "");

                    $(this).attr("text", xtext + " " + "[" + "$" + newtext + "]");
                };





            });







        });


    };

RoccoC5 · Accepted Answer · 2011-08-16 15:13:58Z

2

You can also use a regular expression, as Jon Martin pointed out:

var yum = "donut[$25]"; yum.replace(/[.*?]/, ""); // returns "donut"

answered Aug 16, 2011 at 15:13

RoccoC5

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Jon Martin · Accepted Answer · 2011-08-16 15:10:03Z

1

Alternatively:

var temp = foo.split('[')[0];
var temp2 = foo.split(']')[1];

foo = temp + temp2;

answered Aug 16, 2011 at 15:10

Jon Martin

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Liam · Accepted Answer · 2011-08-16 15:51:38Z

1

You can use regular expressions (the RegExp() object) to match strings.

var foo = "donut[$25]";
foo.match(/\[.*\]/);

The above will return an array of every item in [square brackets], in this case ["[$25]"].

To just get one result as a string, specify the first index like so:

foo.match(/\[.*\]/)[0];

The above will return "[$25]"

Edit: You know what? I completely misread which bit of the string you're after. This is what you're after:

var foo = "donut[$25]";
foo.match(/\w*/)[0];

edited Aug 16, 2011 at 15:51

answered Aug 16, 2011 at 15:18

Liam

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Alex K. · Accepted Answer · 2011-08-16 15:09:31Z

0

How about simply;

var yum = "donut[$25]";
print( yum.substr(0, yum.indexOf("[")) );

>>donut

answered Aug 16, 2011 at 15:09

Alex K.

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4 Comments

Jon Martin Over a year ago

This won't work for strings that have characters after the ']'.

Alex K. Over a year ago

It will work for donut[$34]weqweqwe as it truncates at the 1st [ which seems reasonable for what appears to be structured data

Jon Martin Over a year ago

He only wanted to delete everything between [..] inclusively. Your method will delete everything after the ].

LaserBeak Over a year ago

var xtext = $(this).text().toString(); xtext.substr(0, xtext.indexOf("[")); - Does not seem to be doing anything ?

Mr.J4mes · Accepted Answer · 2011-08-16 15:18:06Z

0

var begin = foo.search("["); var end = foo.search("]"); var result = foo.substr(0, begin) + foo.substr(end+1); //Combine anything before [ and after ]

Should be ok right?

answered Aug 16, 2011 at 15:18

Mr.J4mes

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HBP · Accepted Answer · 2011-08-16 15:32:18Z

0

Your question leaves unspecified the treatment of the spaces before the [ character, anything after the ], will your string ever contain a linefeed character, multiple occurrences of [..], leading or trailing spaces.

The following will replace all occurrences of 'spaces [ ... ] spaces' with a single space, then it trims the result to remove any leading/trailing spaces.

   v.replace (/\s*\[[\s\S]*?\]\s*/g, ' ').trim ();

answered Aug 16, 2011 at 15:32

HBP

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